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  #1  
Old 08-03-2010, 06:33 AM
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225 watts into 2/4/8 ohms...why is the wattage not cut when the ohms go up?

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Just a general question here.

My SVT450 was 225 watts into 8 ohms and 450 watts into 4 ohms.

My new VB-2 is 225 watts regardless of the ohms.

I know one is SS and one is tube, which probably explains something...but can someone explain this to me?
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  #2  
Old 08-03-2010, 06:38 AM
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Originally Posted by panama View Post
I know one is SS and one is tube, which probably explains something...
It explains everything. The current delivery of a SS amp depends on the load impedance; not so with tubes. But to work well into different loads tubes have different impedance taps.
  #3  
Old 08-03-2010, 06:42 AM
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By impedance tap do you mean the 2/4/8 switch on the back of the amp?
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  #4  
Old 08-03-2010, 07:03 AM
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Yes exactly. The SS amps feed the power directly to the speakers as they are low impedance current devices. Tubes on the otherhand are voltage devices and have extrememly high impedance on the order of as high as 8000 ohms. You must match impedances to transfer power. It's like a transmission in a car, you need to select the right gear.

An output transformer in a tube amplifier has windings in a primary and secondary wound over each other. A transformer that can match 8000 ohms to 4 ohms will have a ratio between the number of turns between the primary and secondary of 2000:1.

When you select 8 ohms, the secondary has an additional section of windings the size of the 4 ohm section doubling the size of the coil and that makes the ratio 1000:1. Or if it is easier to follow 2000:2.

The actual number of turns in the windings is not this ratio, but a mutliple of the ratio. Meaning the 4 ohm secondary might have 10 turns on it... If it had 10 turns the primary will have 20,000 turns. It really is that simple.

BOB
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Last edited by rbonner : 08-03-2010 at 07:05 AM.
  #5  
Old 08-03-2010, 07:08 AM
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As a general rule, tube amps have a output transformer with several taps for the output "2-4-8 ohms", they will put out, the full rated power at any of the selected taps,
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Old 08-03-2010, 07:13 AM
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Very cool. Thanks guys!
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  #7  
Old 08-03-2010, 08:25 AM
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Panama, this is probably a better thread to ask in...

Which tap do you use for a 2.67 ohm load?
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Old 08-03-2010, 08:27 AM
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Thanks!

Which tap do you use for a 2.67 ohm load?
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  #9  
Old 08-03-2010, 09:18 AM
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Ideally none of them. It's always best to match impedances exactly for a tube amp.

Paul
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Old 08-03-2010, 09:25 AM
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Well, I guess my idea of a 4ohm 212 + 8ohm 15 is out then. Oh well
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  #11  
Old 08-03-2010, 10:07 AM
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Originally Posted by BassmanPaul View Post
It's always best to match impedances exactly for a tube amp.

Paul
Not really, impedance only being an approximation at best anyway. What transformers don't like is a higher impedance load, so when you don't have a tap that's the same as the load use the next higher rated tap. With a 2.67 ohm load I'd use the 4 ohm tap rather than the 2 ohm.
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Well, I guess my idea of a 4ohm 212 + 8ohm 15 is out then. Oh well
A pair of 212 will work better.
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Old 08-03-2010, 10:35 AM
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All the transformer does is convert the load impedance into a very much higher impedance suitable for the plates of the output tube(s). Running a tube into a less than ideal impedance will shorten tube life until one fails. At that time all hell can break loose.

Paul
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Old 08-03-2010, 11:26 AM
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Most tube amp companies I've talked to have said to use 2 ohm taps for 2.67 ohms.

Myself, I'd steer clear of needing that impedance and use matched cabs.
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Old 08-03-2010, 11:32 AM
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Yeah I think the best bet for right now is to keep my 15e and 410he and wait for someone who ants to trade a 410 for my 15..plus cash probably.
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  #15  
Old 08-03-2010, 12:20 PM
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You'd be really amazed at what the impedance of your cab looks like as you swing the frequency across the range. Just look at any of the charts on the eminence site.

BOB
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  #16  
Old 08-03-2010, 12:38 PM
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Originally Posted by BassmanPaul View Post
Running a tube into a less than ideal impedance will shorten tube life until one fails.

Paul
Care to venture what the impedance is shown here?


The cab shown is an SVT. Impedance varies from roughly 3.5 to 28 ohms, and that's only to 500 Hz. At the right side of the chart impedance continues to climb to well over 100 ohms in the high end.
  #17  
Old 08-03-2010, 01:03 PM
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Quote:
Originally Posted by rbonner View Post
An output transformer in a tube amplifier has windings in a primary and secondary wound over each other. A transformer that can match 8000 ohms to 4 ohms will have a ratio between the number of turns between the primary and secondary of 2000:1.

When you select 8 ohms, the secondary has an additional section of windings the size of the 4 ohm section doubling the size of the coil and that makes the ratio 1000:1. Or if it is easier to follow 2000:2.

The actual number of turns in the windings is not this ratio, but a mutliple of the ratio. Meaning the 4 ohm secondary might have 10 turns on it... If it had 10 turns the primary will have 20,000 turns. It really is that simple.

BOB
Almost correct. The actual ratio is the square root of the impedance ratio. The output voltage is proportional to the ratio, and when the voltage drops so does the current, which drops the output power. To maintain the power the current needs to increase with the same ratio. If the voltage drops to half (assuming a 2:1 ratio), the impedance needs to be reduced by a factor 4 in order for the current to rise to the double.

Working backwards in your example means if you want to go from 8000 to 4 you'll need a ratio of SQRT(8000/4), which is 44:1.

Not that it matters to the question at hand. The impedance selector picks the output with the required ratio, keeping the available power constant.
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  #18  
Old 08-03-2010, 09:52 PM
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Originally Posted by Rune Bivrin View Post
Almost correct. The actual ratio is the square root of the impedance ratio. The output voltage is proportional to the ratio, and when the voltage drops so does the current, which drops the output power. To maintain the power the current needs to increase with the same ratio. If the voltage drops to half (assuming a 2:1 ratio), the impedance needs to be reduced by a factor 4 in order for the current to rise to the double.

Working backwards in your example means if you want to go from 8000 to 4 you'll need a ratio of SQRT(8000/4), which is 44:1.

Not that it matters to the question at hand. The impedance selector picks the output with the required ratio, keeping the available power constant.
Well we're lucky I'm not winding output transformers, I've wound a couple large filament transformers and hit the voltage and current on the head but it was 30 years ago. Thanks for the correction.

BOB
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