TalkBass Forums 8 8ohm speakers to a 4ohm load? help needed.
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#1
01-15-2014, 11:25 AM
 Registered User Join Date: Sep 2005 Location: Portland, OR
8 8ohm speakers to a 4ohm load? help needed.

I'm trying to wire an 8x10 for a friend. Cab needs to be 4 ohms. It's loaded with 8 ohm speakers. Anyone have a wiring diagram? I think I should be able to wire 2 sets of 4 speakers in parallel and then put those two sets in series for a total of a 4 ohm load, but I'm not 100% sure. Any help would be appreciated.
#2
01-15-2014, 11:30 AM
 Registered User Join Date: Aug 2008
(8+8) || (8+8) || (8+8) || (8+8) = 4Ω

+ = serial connection
|| = parallel connection
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#3
01-15-2014, 11:30 AM
 Registered User Join Date: Mar 2006 Location: East Central Wisconsin
Two sets of 4 in parallel and wire the sets in series. That works.
#4
01-15-2014, 11:31 AM
 Registered User Join Date: Sep 2005 Location: Portland, OR
Awesome! Thank you.
#5
01-15-2014, 11:35 AM
 Registered User Sunshine on my shoulders makes me happy Join Date: May 2006 Location: austin,tx
Imagine it as being a pair of 8ohm 410's, then parallel them together. Should have a DCR reading between 3 and 4 when you're done.
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#6
01-15-2014, 12:28 PM
 Registered User Join Date: Jan 2013 Location: Squierville, California
You have two options and both of them have been described previously : A) series pairs and all pairs in parallel OR B) parallel pairs and all pairs in series. The primary difference will be what happens if one speaker fails. With option A, if one speaker fails its mate in series will stop working also. With option B, if one speaker fails all of the others will continue playing. If the cabinet is one that is constructed SVT-style with pairs of speakers in separate chambers then I think option A would be best because it has a safer failure mode. If one speaker in a chamber fails the other speaker in that chamber will likely follow its mate in short order if it continues to play. I think it is safest for it to just stop playing. If the cabinet does not have separate chambers then the decision is less clear for me but I would probably choose option A in that case too.
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#7
01-16-2014, 06:34 AM
 Registered User Join Date: Aug 2008
For a graphic, here is option A [ (8+8) || (8+8) || (8+8) || (8+8) = 4Ω ]. +1 and -1 is for a speakon connector.

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Official Ampeg Portaflex Club #89

Last edited by beans-on-toast : 01-16-2014 at 06:39 AM.
#8
01-16-2014, 04:44 PM
 Registered User Join Date: Sep 2005 Location: Portland, OR
That is exactly what I needed. Thanks a ton.
#9
02-04-2014, 06:55 PM
 Registered User Join Date: May 2011
So "Hypothetically" would this work if one wanted to build a "Franken Cab" with say 12 10's..... I was just wondering what that would sound like...
#10
02-04-2014, 07:34 PM
 Registered User Join Date: Aug 2008
If you built one like in the example above but with twelve tens, it would come out to 2.7 ohms. Why stop at twelve, even better would be sixteen tens, two 810 cabs, at four ohms each. A SVT can take 2 ohms so you could connect them both. Two 810 cabs would sound twice as good as one 810 cab.
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Official Ampeg Portaflex Club #89

Last edited by beans-on-toast : 02-04-2014 at 07:40 PM.

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