adjusting watts for 2 cabs

[Buzter]

running 2 cabs off one amp. Any way to adjust how many watts going to each cab? Daisy chain make any difference?

[billfitzmaurice]

Originally Posted by Buzter

running 2 cabs off one amp. Any way to adjust how many watts going to each cab?

No.

[Mr. Foxen]

Volume control adjusts the watts going to the cabs, but the proportion between them will be the same. Get a stereo power amp, and you can have a volume control for each.

[Bassmec]

Originally Posted by Buzter

running 2 cabs off one amp. Any way to adjust how many watts going to each cab? Daisy chain make any difference?

It depends on all the information you didn't supply, like your amplifiers minimum ohms (better still manufacturer & model) the no of loudspeakers in each cabinet and their individual
and collective impedance per cabinet.

[GizmoTheOne]

Originally Posted by Mr. Foxen

Volume control adjusts the watts going to the cabs, but the proportion between them will be the same. Get a stereo power amp, and you can have a volume control for each.

This.

[Buzter]

Shucks.... It's an acoustic b600h, ampeg svt-hlf410(4ohms), acoustic b115 cab(8ohms). The amp is cap. of doing 2 ohms. Just seems like there is more signal coming from the 115.

[Caca de Kick]

Well actually, when you are using two non-matching impedence cabs, the 4ohm cab is going to draw more power from the head than the 8ohm cab.
For example; if that head puts out 600w, then the 4ohm 4x10 is drawing 400w, and the 8ohm cab is drawing the other 200w.

If you had two same impedence cabs, then of course the power is split equally to each cab.

You're probably just hearing the mids of the 15 better, since the HLF cabs tend to be bassy.

[billfitzmaurice]

Originally Posted by Buzter

Shucks.... It's an acoustic b600h, ampeg svt-hlf410(4ohms), acoustic b115 cab(8ohms). The amp is cap. of doing 2 ohms. Just seems like there is more signal coming from the 115.

There are a number of reasons why this could happen, and nothing you can do about it without using a second amp. This is one of the reasons why mixing cabs isn't a good idea.

[JimmyM]

Originally Posted by billfitzmaurice

There are a number of reasons why this could happen, and nothing you can do about it without using a second amp. This is one of the reasons why mixing cabs isn't a good idea.

Especially those two cabs.

[bongomania]

Originally Posted by Mr. Foxen

Volume control adjusts the watts going to the cabs

Barely true. The volume control is part of the story, but it is not literally directly a control over the wattage the amp puts out.

For an illustration, imagine there's a device in your car that can slow it down by 10 mph, from whatever speed you would have been going without that device. So you would normally have been going 70, and it slows you down to 60; or you'd have been going 80, and it slows you down to 70. Clearly the device is affecting your speed, but you can still drive at 70 if you want. That's how the volume knob works: it turns down your levels a fixed amount, but if you drive the input of the amp harder, you can put out the same amount of wattage that you would have without the volume knob turned down.

[Buzter]

well I do have a second amp...a b200h. How would I run them together to get the signal from the bass to both amps?

[bongomania]

One option is to use a splitter, like a stereo chorus pedal or a Lehle P-Split or an [sfx] split pedal, to Y the bass to the input of both amps. You can also try using a passive ABY box or a passive Y cable, but those open up some possibility for tone suckage.

The other option is to take the line out (not the speaker out!) of one amp head, and run it into the input of the other amp head. This is the method I would recommend, because you don't have to buy or fuss with a special splitter device.

[Buzter]

thanks for the comments.

[kosmicwizard]

Buzter,

How does it sound to you when you run the B600H into the 410HLF and the B200H into the B115? Do you like the 115 on top better than on the bottom? Whatever you do, let your ears deside what the solution is and please get back to us with your findings. Cheers.