(before someone say search the forum, I did

)
I have a Seymour Duncan Biamp 8000 that is able to run in a few combinations, bridged giving 600w @ 8 ohms, dual mono giving 2x400w @ 4 Ohms or in Biamp mode sending high frequencies to one cab and low to another (also optimal load being 2x400w @ 4 ohm..)... if running in biamp you can set the cross over point at anything from 100hz to 1khz...
You also than have 2 separate volume knobs for high and low...
Ok, here's the thing, I got a 410 cab that is rated 240w @ 8ohm (original hartke xl) but I was toying with the idea of getting 15" extension cab and would like to run that in 4ohms.. (and have a bit more watt on tap with the 15" cab not yet acquired, so maybe looking at a 3-500w @ 4ohm 15" cab??
My reasoning behind this is, I like the hartke's "snap" and top end clarity but want more power and warmth in the low end. So by feeding the low end cab the 4 ohm that'll give it more volume then what I'm "serving" up to the hartke cab with 8 ohm, right?
IE, using the 15" for the fundamental bass sound and just topping up the tops clarity with the hartke cab and letting that cab take care of things at the say over 600hz or so...
Here's my questions: Am I missing something fundamental in my reasoning? And, as the biamp 8000 manual states that it's optimal load is 2 x 4ohms, the way I understand it, it would be perfectly safe to run 1 4ohm 15" cab and 1 8ohm 410 cab in biamp mode and I should be able to use the volume knobs to balance sound (being fully aware that the 410 cab would get less watt... but since it only has to deal with "easier" frequencies and won't have to deal with the duties of the low end, it should be plenty enough ???
Anyone with knowledge are free to theories with me here even if you don't have experience with that sort of set up..
If I don't make any sense, it might be to the fact that English isn't my first language but I'm more then happy to further explain what I want to achieve.