Here's the conundrum. Looking at doing a pair of cabs to match the footprint of a specific amp, Peavey Classic400, big tube amp. Needing the footprint limits me to building however high I need to reach a workable internal volume.
What if the height ends up equaling the width? In this case, that's 23". Looking at the boundry cancellation chart,
http://www.padrick.net/LiveSound/CancellationMode.htm 23" is 1/4 wavelength at 7.66 ft. That ends up between 35 and 40hz. Total non-issue if that gets cancelled out. 23" is a full wavelength between 145 and 150hz, do not want to lose output there.
Are these cancellations really narrow? Does having 2 dimensions the same measurement make the cancellation deeper but no less narrow?
The depth is 15", that's 1/4 wavelength at 5 feet or between 55 and 60hz. Don't want to lose output there. It's also a full wavelength between 225 and 230hz.....really don't want to lose anything there but I have other cabs with similair depth and they don't seem to be missing anything.
Are these cancellations, although they may add up to a lot of db, in such a narrow bandwidth where I'm over-thinking this? Will it really screw things up if 2 of the 3 dimensions are equal?
Edit: Should note that I've read things saying it's a bad idea to build a cube, ie: 3 equal dimensions. Also read that the "ideal" ratio should be .6 depth to 1 width to 1.6 height although I haven't reverse engineered these to figure out why or what you lose by not doing it that way.
Another Edit: Rule of thumb is never put a sub 6 feet from the wall. That's a full wavelength cancellation between 45 and 50hz. Using the 1/4 wavelength method would put you at 18" or between 185 and 190hz. That should be close to or above where you should lowpass a sub at so I'm not sure if I'm calculating the cancellations correctly using the 1/4 wavelength or full wavelength method or maybe going the wrong way, multiply instead of divide?
Thanks