Can't get the diagram to post.
Go about 3/4 of the way down the page until you see this:
"2 sets of 3 speakers in parallel, with those 2 sets in series:
For 4 ohm speakers, you get a 2.67 ohm load.
WARNING:Power amp must be able to drive a 2 ohm load
For 6 ohm speakers, you get an 4 ohm load.
For 8 ohm speakers, you get a 5.34 ohm load.
For 16 ohm speakers, you get a 10.66 ohm load."
Here:
http://www.colomar.com/Shavano/spkr_wiring.html
Basically you connect the + terminals of 3 speakers running down one side of the cab to the + terminal of the jack. Then connect the - terminals of the 3 speakers running down the other side of the cab to the - terminal of jack. Then use a jumper to connect the remaining open + and - of each pair. It's like wiring a 410 with 2 extra speakers strung to it. In this case it will technically come to 5.33 which would be marketed as a 4ohm cab for amplifier protection/chaining cabs, etc. The difference in amp power between 4 and 5 ohms is for practical purposes nothing.
The tweeter is likely a high pass filter only meaning the woofers are playing the whole signal and just the lows are kept away from the tweeter. If it is a true crossover, where it takes treble out of the woofers too it'll have more than one coil on the circuit board. Simply....just connect the tweeter the way it was.
