Go Back   TalkBass Forums > Bass Guitar Forums > Bass Guitar Forums > Amps [BG]
Register Rules/FAQ/CUP Members List Search Today's Posts Mark Forums Read



Supporting Membership
Thank You

Latest Supporting Member
Donate to Upgrade Today

Reply
 
Thread Tools Search this Thread
  #1  
Old 02-24-2011, 02:29 PM
pica's Avatar
Registered User
 
Join Date: Nov 2009
Location: Metro Detroit
Supporting Member
Ohms, Amps & Speakers

Sign in to disble this ad
I came across this web page while trying to learn about Ohms. Thought some of you beginners out there would like to read this. Has some very informative information.

http://www.marktaw.com/recording/Ele...dSpeakers.html
  #2  
Old 02-24-2011, 02:44 PM
BassmanPaul's Avatar
Registered User
 
Join Date: Aug 2007
Location: Toronto Ontario Canada
GOLD Supporting Member
The whole subject of impedance gets blown out of all proportion. In reality it's so simple. As most individual drivers are 8Ω, if you are paralleling them you simply divide 8 by the number of drivers. Two: 8/2=4, three: 8/3=2.67 etc. There is simply no need to go into high mathematics to work out what a total impedance will be.
__________________
Paul
  #3  
Old 02-24-2011, 03:33 PM
Registered User
 
Join Date: Feb 2010
Location: Nude Zealand
It's slightly trickier if you're using cabs with different impedance ratings, but the total impedance (R) =

1/([1/R1] + [1/R2] + [1/R3] + ...)

where Rn is the impedance of each attached cabinet/speaker wired in parallel. Still not that difficult .
__________________
Christopher 401T / Gage Realist Soundclip / Fishman Pro-EQ Platinum Bass / fdeck HPF-Pre Series 2
NS Design CR4M EUB / TC Electronic RH450 & Markbass F1 / BFM Jack 112
  #4  
Old 02-24-2011, 04:48 PM
BassmanPaul's Avatar
Registered User
 
Join Date: Aug 2007
Location: Toronto Ontario Canada
GOLD Supporting Member
Quote:
Originally Posted by GrowlerBox View Post
It's slightly trickier if you're using cabs with different impedance ratings, but the total impedance (R) =

1/([1/R1] + [1/R2] + [1/R3] + ...)

where Rn is the impedance of each attached cabinet/speaker wired in parallel. Still not that difficult .
No Sir it is not. With differing impedances you convert into 8Ω blocks. Example 4Ω in parallel with 8Ω. 4Ω is two parallel 8Ω blocks so 4Ω (8x2) plus one 8Ω block = 3 8Ω blocks. 8/3 is 2.67Ω. It IS so simple.
__________________
Paul
  #5  
Old 02-24-2011, 06:34 PM
Registered User
 
Join Date: Aug 2004
Now that you figured out total impedance, keep in mind what the power delivered to each speaker is.
__________________
"The good thing about science is that it’s true whether or not you believe in it." - Neil DeGrasse Tyson 2011
  #6  
Old 02-24-2011, 10:40 PM
Registered User
 
Join Date: Feb 2010
Location: Nude Zealand
Quote:
Originally Posted by BassmanPaul View Post
No Sir it is not. With differing impedances you convert into 8Ω blocks. Example 4Ω in parallel with 8Ω. 4Ω is two parallel 8Ω blocks so 4Ω (8x2) plus one 8Ω block = 3 8Ω blocks. 8/3 is 2.67Ω. It IS so simple.
How is that different? 1/[1/4] + [1/8] = 8/3
__________________
Christopher 401T / Gage Realist Soundclip / Fishman Pro-EQ Platinum Bass / fdeck HPF-Pre Series 2
NS Design CR4M EUB / TC Electronic RH450 & Markbass F1 / BFM Jack 112
Reply


Thread Tools Search this Thread
Search this Thread:

Advanced Search

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are Off
Refbacks are Off

Follow TalkBass on Twitter   Visit TalkBass on Facebook  

All times are GMT -6. The time now is 11:21 PM.




Copyright 2011 Talk Music Group Inc. All rights reserved.
Play guitar? Visit our new sister site TalkGuitar.com [beta]
Powered by vBulletin® Version 3.6.12
Copyright ©2000 - 2012, Jelsoft Enterprises Ltd.