PF800/General SS head and cab impedance question
Hypothetical question here (and yes I've poured over all the amp stickys and still not sure if I've got a full grasp or the right answer) so please help clarify if you can:
Looking into a PF800 as a backup to play with an Orange OBC410 cab. Cab is rated at 8ohms, 600W. It's listed that the Ampeg will push 400W on an 8ohm load, so it should be golden. Also planning to possibly swap with an OBC115 depending on gig or preference (400W at 8ohms) which would still be in an okay range for impedance.
Here's the question (and yes I've read about the negatives of pairing mismatched cabs, so please refrain from lecturing me on that, but), if I were to hypothetically run both cabs in parallel (which would put the output of the Ampeg at 4ohm, 800W), how is that power divvied up? Is 800W supplied to both cabs simultaneously (meaning both my cabs would be underrated for the power supply at that point), or is the 800W divided up between the two cabs (maybe unequally at that point since they are mismatched drivers) putting it at less than 800W?
Any light on this subject you guys could lend without pointing me back to the stickys would be awesome.
The power is divided by each cab. Each gets half.
So I'd still be in okay territory with cab impedance.
Well, that's good news.
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