|  | 
07-05-2011, 10:17 AM
| | | | Is this safe?
Sign in to disble this ad
I have the GK MB500.
It says it can do 500watts at 4 ohms or 350watts at 8 ohms.
I have a cab that says 8 ohms, 300 watts.
Can I use them together and if so is there anything I should avoid? |
07-05-2011, 10:21 AM
| | Registered User | | Join Date: Jul 2009 Location: Willmar, Minnesota | | | You're good to go. Use your ears when you turn it up. If it distorts, turn it down. I don't foresee that happening IMHO.
__________________
Education: the path from cocky ignorance to miserable uncertainty.
|
07-05-2011, 10:22 AM
| | Registered User | | Join Date: Jan 2010 Location: Vancouver | | | Yes, you can, just gotta be careful and not crank the head too high. Adjust the volume with your ears, not your eyes.
But that cab sounds like either a 115 or a 210, so it's got its limits and it could fart out much earlier than 300W. You may want to add another 8 ohm cab if you want more volume. |
07-05-2011, 10:30 AM
| | | Quote:
Originally Posted by Alex1984  Yes, you can, just gotta be careful and not crank the head too high. Adjust the volume with your ears, not your eyes.
But that cab sounds like either a 115 or a 210, so it's got its limits and it could fart out much earlier than 300W. You may want to add another 8 ohm cab if you want more volume. | It's a Hartke vx 115. Would I have enough volume to play with a drummer? Not a loud drummer, but a moderately loud one. |
07-05-2011, 10:31 AM
| | | | What does 300watts @ 8 ohms actually mean? Could someone give as specific an explanation as possible please. |
07-05-2011, 10:42 AM
| | Registered User | | Join Date: Jan 2008 Location: YTZ | | Quote:
Originally Posted by eoinwalsh What does 300watts @ 8 ohms actually mean? Could someone give as specific an explanation as possible please. | you talking bout the head or the cab?
__________________
In-A-Gadda-Da-Vida
|
07-05-2011, 11:26 AM
| | | | the cab |
07-05-2011, 11:36 AM
| | Registered User | | Join Date: Jan 2008 Location: Bay Area, CA | | | The voice coil can take 300 watts, I'm going to assume, RMS. Which means it won't melt down if it is getting 300 or less watts continuously.
Which really means nothing it seems since speakers don't usually fail from heat, but from mechanical limits, i.e bottoming out or over excursion. |
07-05-2011, 11:41 AM
|  | I'm just a cover of a real bassist | | Join Date: Dec 2010 Location: 6.7 m (22 ft) below sea level | | | The power delivered in a certain impedance is the product of the voltage accross it and the current through it. Derived, one could say that the power through a resistor equals the current to the power of two times the resistance value. So: 300 W devided by 8 Ohms gives 37.5. This is the current squared. The root of 37.5 equals 6.124 (rounded) Amps. Now that we know the current, we can calculate the voltage accross the speaker. 300 Watts devided by 6.124 gives almost 49 Volts. So back to your question: the cab is specified to be able to withstand a voltage of 49 volts to from the cab. This is not continuous, as we are dealing with very complex alternating currents here. The example applies to direct current, hawever it can be used for understanding the basics of electrical power in relation to resistance. In case of a 4 Ohm speaker the current would be a little higher: 8.66 Amps. The voltage would drop to just under 35 Volt.
Keep on playing subsonically!
Last edited by Jay2U : 07-05-2011 at 11:44 AM.
|
07-05-2011, 12:00 PM
| | Registered User | | Join Date: Jan 2008 Location: Bay Area, CA | | | |
07-05-2011, 12:43 PM
|  | Bassist at The Blood Of Royals | | Join Date: Jan 2011 Location: Dayton, Ohio | | Quote: |
Originally Posted by Jay2U The power delivered in a certain impedance is the product of the voltage accross it and the current through it. Derived, one could say that the power through a resistor equals the current to the power of two times the resistance value. So: 300 W devided by 8 Ohms gives 37.5. This is the current squared. The root of 37.5 equals 6.124 (rounded) Amps. Now that we know the current, we can calculate the voltage accross the speaker. 300 Watts devided by 6.124 gives almost 49 Volts. So back to your question: the cab is specified to be able to withstand a voltage of 49 volts to from the cab. This is not continuous, as we are dealing with very complex alternating currents here. The example applies to direct current, hawever it can be used for understanding the basics of electrical power in relation to resistance. In case of a 4 Ohm speaker the current would be a little higher: 8.66 Amps. The voltage would drop to just under 35 Volt.
Keep on playing subsonically! | This would be hard to follow for people who aren't electrical savvy |
07-05-2011, 02:52 PM
| | I'm just a cover of a real bassist | | Join Date: Dec 2010 Location: 6.7 m (22 ft) below sea level | | Quote:
Originally Posted by Mybikeisblack This would be hard to follow for people who aren't electrical savvy | Yep, I know. I'm only trying to be helpful by sharing knowledge in my own simplistic way. If I were better in explaining stuff to others, I might be have become a teacher. I haven't, I'm a technician who tries to understand how to play the bass.  | | Thread Tools | Search this Thread | | | | 
Posting Rules
| You may not post new threads You may not post replies You may not post attachments You may not edit your posts
HTML code is Off | | | |
