Quote:
Originally Posted by Jarrett Let's say I have a 2ohm capable (BX500) amp running mono
So you are saying I'd want the 8ohm 2x10 paired with the 4ohm 4x10? Why is that? |
Yes. That combination would result in 2.67ohm nominal impedance, and each driver would get the same power (i.e., the 8ohm 210 with half the drivers of your 4ohm 410 will get half the power).
So, basically, you have created a 2.67ohm modular 610. The downside is you have to have a head capable of 2ohm or so operation. The upside is that you have a 'three use' modular system that automatically adjusts power for the speaker size... 210 8ohm, smallest cab, lowest power for small gigs, 410/4ohm, single large cab/high power for most gigs, 210(8ohm)/410(4ohm) most drivers, highest power for your biggest, loudest gigs.
Think about it this way (regarding the different impedances of the cabs), you wouldn't want two of the six drivers in a 610 to each get twice the power versus the other 4 drivers. Same thing with the 210/410 (assuming the cabs use the same drivers).
Edit: This doesn't mean that other combinations (8/8ohms or 4/4ohms) won't work... just doesn't make as much sense.