Originally Posted by sailorofcheese
hi, hopefully you can answer my question. i have a trace elliot ah1000-12 and i dont know if im reading this correctly in my manual.
"There are two speaker output jack sockets provided, allowing two speaker cabinets to be connected to the amplifier. The combined impedance of these speaker cabinets must not be less than 4 ohms. Two 8ohm cabinets is the ideal load for these amplifiers.
If you are using one 4ohm cabinet, then no further speakers can be connected to the amplifier or the combined impedance will fall below 4 ohms. If this occurs you will just be wasting power in heat generated by the output stage and no more volume will be available than with the single 4ohm cabinet."
so what they're saying is. two 8ohms is better, one 4ohm cab alone is the limit.? thats what im getting out of it. i just dont want to make a mistake.....
There's no "better". It's just like Deacon said, above:
- 2 speaker jacks
- Combined load must not be LESS THAN 4 ohms
- 2 @ 8 ohm cabinets is the IDEAL load
Above suggests strongly that the 2 jacks are wired in parallel
. (8 * 8) / (8 + 8) = 64/16 = 4 ohms combined, which is the stated minimum limit for the amp.
"If you are using one 4ohm cabinet, then no further speakers can be connected to the amplifier or the combined impedance will fall below 4 ohms." Should be pretty obvious, however (assuming the 2nd cabinet is also 4 ohms):
(4 * 4) / (4 + 4) = 16/8 = 2 ohms - well below
the minimum impedance, & very likely to release some magic smoke!
How about a 4 ohm with an 8 ohm?
(4 * 8) / (4 + 8) = 32/12 = 2.67 ohms - still not good (below the minimum).
2 @ 16 ohm?
(16 * 16) / (16 + 16) = 256/32 = 8 ohms - that'll work just fine, because it's at or above
the stated minimum
Etc. for various other speaker combinations. If you go beyond 2 speakers, you have to multiply all
the impedances, and divide that by the sum of all
the impedances. The math is easiest if you stick to 2 or fewer speakers.
Again, though, there's no "better" or "worse" unless you get below the threshold where you can damage something.