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06-29-2011, 09:44 PM
| | | | Replaceing 4ohm speakers with 8ohms?
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Hi everyone. I have an old pair of PV's 18 inch subs that we use live and I run them stereo on my amp cause they are 4 ohms and the amp cannot be bridged below 4ohms and if I bridge them out and run them parallel then I have 2 ohms. SO I was wondering if I could simply pull the black widows out and replace them with 8 ohm subs with higher power ect so I can do just that and get an extra 300 watts a piece by bridging the amp and running them parralel?? Thanks a lot!! |
06-29-2011, 10:30 PM
| | Registered User | | Join Date: Jan 2004 Location: montana | | | Probably not worth the effort. If you put a new subwoofer in that isn't designed for the cabinet it could sound worse or else the speakers could destroy themselves.
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06-29-2011, 11:21 PM
| | Registered User | | Join Date: Dec 2000 Location: Portland, OR | | | Why not just wire it/them in series and make them 8 ohm... for free?
In series it's 4x2=8 ohm
in parallel it's 4/2=2 ohm
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06-30-2011, 01:12 AM
|  | Total Hyper-Elite Member | | Join Date: May 2000 Location: Groom Lake, NV | | Yes, a series cable is the way to go. 
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What is this thing called butthurt? |
06-30-2011, 03:18 PM
| | | | Interesting so I just plug each of those ends into each bass cab, and the single end into the amp, bridge it out and it will be bridging in 4ohms instead of 2? |
06-30-2011, 07:42 PM
| | | | pointless, as bridging into the resulting 8Ω load will net you the same power as running each 4Ω box into one side of the amp like you have now.
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Walter Wright
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Alpha Music, VA Beach
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07-02-2011, 01:16 PM
| | | | Im actually running one sub on each side of the amp in stereo mode which puts out 425 watts to each. If I could bridge it by using the middle post it would put out 1475 watts to them at 4 ohms. I take it that running them in series will keep it at 8 ohms and not 4 ohms? |
07-03-2011, 10:52 PM
| | | | yep, series just straight adds together, so you'd have an 8Ω load, and pretty much the same power as one cab into each side of the amp.
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Walter Wright
Guitar Repair Gnome
Alpha Music, VA Beach
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07-03-2011, 11:58 PM
| | Total Hyper-Elite Member | | Join Date: May 2000 Location: Groom Lake, NV | | Quote:
Originally Posted by texastone  Interesting so I just plug each of those ends into each bass cab, and the single end into the amp, bridge it out and it will be bridging in 4ohms instead of 2? | Exactly. I made that one and another one with Speakon ® plugs.
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What is this thing called butthurt? |
07-12-2011, 11:20 AM
| | Registered User | | Join Date: Jan 2003 Location: good 'ol USA/Tampa fla. | | Quote:
Originally Posted by Tracebassplayer Why not just wire it/them in series and make them 8 ohm... for free?
In series it's 4x2=8 ohm
in parallel it's 4/2=2 ohm | this would be the way to go |
07-12-2011, 10:58 PM
| | | Quote:
Originally Posted by Tracebassplayer Why not just wire it/them in series and make them 8 ohm... | because (to repeat) you wouldn't gain anything!
an amp bridged into 8Ω will create pretty much the same power as one getting 4Ω per side stereo.
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Walter Wright
Guitar Repair Gnome
Alpha Music, VA Beach
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07-13-2011, 08:40 AM
| | Registered User | | Join Date: Apr 2007 Location: Cahir, Tipperary,Ireland | | | There is no way to make two 4 ohm loads behave as one 4 ohm load with out introducing a lot of extra circuitry
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