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Western music is based on the Twelve-Tone Equal Temerament (12-TET). This is a schema by which an Octave is divided into series of equal frequency ratios. The calculation for the below values is a bit complex, so I havn't gone into much detail about that.
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It's not that difficult.
If you plot perceived pitch against frequency, you find it follows a logarithmic curve to the base 2.
That sounds a bit tricky, but all it means is that each time you go up an octave, pitch is doubled.
A1 (open A on the bass) = 55 Hz
A2 (second fret on G string) = 110 Hz
A3 (14th fret, G string) = 220 Hz
A4 = 440 Hz
A5 = 880 Hz, etc.
A2 = A1*2
A3 = A1*4 (or A1*2*2 = A*2^2)
(that "^2" means "squared" in the absence of superscripts)
A4 = A1*8 (or A1*2*2*2 = A*2^3)
A5 = A1*16 (or A1*2*2*2*2 = A*2^4)
And (because this becomes important below)...
A2 = A1*2 ( = A1*2^1)
But what about steps smaller than an octave? In equal temperament, which is how most guitars are tuned, the octave is divided into 12 equal steps.
If we take the octave as being 2^1 times greater than the starting pitch, as shown above, the semitone is 2^(1/12) times greater than the starting pitch.
This 2^(1/12) (also described as the twelfth root of 2) is kind of a magic number when it comes to equal temperament instruments as it also defines string lengths... the length of the string from the first fret to the bridge is equal to that of the nut to the bridge divided by 2^(1/12)