Chemistry Help?

[bassman03]

I've seen people asking for some help physics and calculus, soooo any here able to help me with chemistry? I've got things for the most part, but its some small technical stuff that's frustrating me. Any help is more than welcomed.

1. Write the formula equation, the overall ionic equation, and the net ionic equation for the neutralization reaction involving aqueous solutions of Sulfuric Acid (H2So4) and Aluminum Hydroxide (Al(OH3)). Assume the Aluminum Hydroxide is completely soluble. Hydronium ion must be present somewhere.


2. Write the overall and ionic equation and the net ionic equation for this reaction: Na(s)+H3Po4(aq). Hydronium ion will appear somewhere. What was oxidized and what was reduced?


3. A seashell, composed largely of calcium carbonate (CaCO3) is placed in a solution of Hydroiodic Acid (HI). As a result, 1324 mL of dry CO2 gas at STP is produced. The other products are calcium iodide (CaI2) and water.
A. Based on this information, how many grams of CaCO3 are consumed in the reaction.
B. What volume of 2.4M HI solution is used in this reaction

Thanks in advance!

Edit: If this is your first time reading it, I realize a should have had my current work with the original post. What I have is some posts down.

[Angus]

Take a full stab at it first, and I'll correct whatever goes wrong.

[Big_Daddy]

Had I been asked this a year ago when it was still fresh, and had it been in French, I may have known.

[ehque]

+1 to Angus.

I can correct mistakes as well (some Uni level chem) but I'm not about to do your homework for you.

[bassybill]

Originally Posted by Angus

Take a full stab at it first, and I'll correct whatever goes wrong.

Originally Posted by ehque

+1 to Angus.

I can correct mistakes as well (some Uni level chem) but I'm not about to do your homework for you.

Same here.

[i_got_a_mohawk]

Originally Posted by bassman03

I've seen people asking for some help physics and calculus, soooo any here able to help me with chemistry? I've got things for the most part, but its some small technical stuff that's frustrating me. Any help is more than welcomed.

Chemistry is a very technical subject. If you are frustrated by the technical part, you don't got things for the most part

Originally Posted by bassman03

1. Write the formula equation, the overall ionic equation, and the net ionic equation for the neutralization reaction involving aqueous solutions of Sulfuric Acid (H2So4) and Aluminum Hydroxide (Al(OH3)). Assume the Aluminum Hydroxide is completely soluble. Hydronium ion must be present somewhere.

This is pretty simple, if you don't understand how to approach it, have a look at your notes or similar examples and see how they have been written out.

Originally Posted by bassman03

2. Write the overall and ionic equation and the net ionic equation for this reaction: Na(s)+H3Po4(aq). Hydronium ion will appear somewhere. What was oxidized and what was reduced?

As above. A simple way to remember which is which with oxidation and reduction:

Oil Rig - Oxidation is Loss, Reduction is Gain. Sounds stupid, but we were taught that really early on in chemistry and I still remember it now.

Originally Posted by bassman03

3. A seashell, composed largely of calcium carbonate (CaCO3) is placed in a solution of Hydroiodic Acid (HI). As a result, 1324 mL of dry CO2 gas at STP is produced. The other products are calcium iodide (CaI2) and water.
A. Based on this information, how many grams of CaCO3 are consumed in the reaction.
B. What volume of 2.4M HI solution is used in this reaction

This one is a bit more involved, but again, is relatively simple. Have a bash at them all and we can help you solve problems where they arise.

Not going to just dish out the answers for your homework tho

[Chebass88]

Originally Posted by i_got_a_mohawk

...As above. A simple way to remember which is which with oxidation and reduction:

Oil Rig - Oxidation is Loss, Reduction is Gain. Sounds stupid, but we were taught that really early on in chemistry and I still remember it now.
...

I learned this as "LEO the lion says GER" (loss of electron is oxidation, and gain of electron is reduction).

Here are some hints for your problems:
For problem 3: Use your favorite equation of state (ideal gas equation would suffice), and from this result, coupled with your balanced equation, it is a simple stoichiometry problem.

Also: On problem 3 - watch your units carefully.

I also am not going to do your problems, but #3 is not a hard one - a little bit of algebra, balanced reactions, and basic rules & you'll be on your way.

ian

[Phalex]

Originally Posted by bassman03

composed largely of calcium carbonate (CaCO3)

I have no idea about any of this stuff, but how are you supposed to come up with an exact measurement given this parameter??

[i_got_a_mohawk]

Originally Posted by Phalex

I have no idea about any of this stuff, but how are you supposed to come up with an exact measurement given this parameter??

That's what you are trying to calculate

You have the result, so you take the assumption that all of the calcium carbonate reacts to give the 1324 mL CO2 (so you can calculate how much calcium carbonate must have been present). You then calculate how much Hydroiodic Acid is used in the experiment.

[Phalex]

Originally Posted by i_got_a_mohawk

That's what you are trying to calculate

You have the result, so you take the assumption that all of the calcium carbonate reacts to give the 1324 mL CO2. You then calculate how much Hydroiodic Acid is used in the experiment.

Ah! Gotcha! Kind of a weird algebraic solve for "X" scenario.

Yeah.... Good luck with that......

[Angus]

This is one of those "do it for me! But ifnot I've posted it elsewhere on the Internet so I can find someone who will."

The "I've got things for the most part" followed by "I've attempted no part in this problem...even the most basic portion" is usually the tip-off that he has not even consciously read the whole problem.

[Chebass88]

Originally Posted by Phalex

Ah! Gotcha! Kind of a weird algebraic solve for "X" scenario.

Yeah.... Good luck with that......

Actually, it is quite easy, and is nothing more than a simple HS chemistry problem.

[champbassist]

I want to post the whole solution so bad But I guess the others are right. You should attempt it yourself and show us where you're facing problems.

[ehque]

Also, if it helps for question 1 and 2, aqueous solutions contain an abundance of water, which means that H₂0, OH^- and H⁺ will be available for reaction, given certain conditions.

[bassman03]

Originally Posted by Angus

This is one of those "do it for me! But ifnot I've posted it elsewhere on the Internet so I can find someone who will."

The "I've got things for the most part" followed by "I've attempted no part in this problem...even the most basic portion" is usually the tip-off that he has not even consciously read the whole problem.

Please don't try to put words into my mouth. I had done them for the most part but some fine details were nagging at me. No where in the original post did I say that "I've attempted no part in this problem...even the most basic portion." I didn't here for a gimme answer like you say I did, or to get out of doing my own work like some other people have suggested. I know people on here have some intellect and would be able to help me out. I do realize now that I should have posted what I had already but I was rushed for time when I originally posted.

Since I'm back home from a day of school now, I'll post what I have.

1. Formula Equation: 3H₂SO₄ + 2Al(OH)₃ --> Al₂(SO4)₃ + 3H₂O
Overall Ionic Equation: 6H⁺ + 3SO₄^2- + 2Al³⁺ + 6OH^- --> 2Al³⁺ + 3SO₄^2- + 3H₂O
Overall Ionic Equation (with added H₂O for Hydronium Ion): 6H₃O⁺ + 3SO₄^2- + 2Al³⁺ + 6OH^- --> 2Al³⁺ + 3SO₄^2- + 9H₂O
Net Ionic Equation: 6H₃O⁺ + 6OH^- --> 9H₂O

For this one I've got the reactants and products right I believe, but the numbers aren't coming out right. It's probably something simple that I'm overlooking.

2. This is the one that's giving me the most troubles. I know that it's a single replacement so I'll get 3Na(s) + H₃PO₄ --> 1.5H₂ + Na₃PO₄
What I'm not quite remembering is how I'm supposed to do this one. Teacher gave an example, and I thought I had it somewhere but I'm not finding it.

3. I was able to figure this one out. Comes to (I think) 5.93 grams for part A, and 49 mL for part B

[i_got_a_mohawk]

I haven't had a chance to do them, and won't tonight (just off to hit the hay, it's midnight here).

But don't get ratty with other members. Read your post. Imagine someone else had posted it. It screams of someone having not done the work and expecting other people to just hand out the answers.

[bassman03]

Originally Posted by i_got_a_mohawk

I haven't had a chance to do them, and won't tonight (just off to hit the hay, it's midnight here).

But don't get ratty with other members. Read your post. Imagine someone else had posted it. It screams of someone having not done the work and expecting other people to just hand out the answers.

I already acknowledged I set myself up for that. It was when he put in quotation marks something that I didn't say that I didn't take too kindly too.

[Chebass88]

Your equations for problem 1 are not balanced, and should be.

From the law of conservation of mass - mass is neither created nor destroyed. If you have 9 hydrogens on the left, you need to have 9 on the right. Same for every element.

**also, thank you for using the super / subscripts **

[ehque]

Originally Posted by bassman03

2. This is the one that's giving me the most troubles. I know that it's a single replacement so I'll get 3Na(s) + H₃PO₄ --> 1.5H₂ + Na₃PO₄
What I'm not quite remembering is how I'm supposed to do this one. Teacher gave an example, and I thought I had it somewhere but I'm not finding it.

Consider the hint i posted above. What happens when you put H₃PO₄ into water? What happens when you put Na(s) into water? Na does not directly react with H₃PO₄ in this case, which is why you are missing essential ions.

Originally Posted by bassman03

3. I was able to figure this one out. Comes to (I think) 5.93 grams for part A, and 49 mL for part B

Show your working?

[jmattbassplaya]

Chemistry ain't my thing. Biology, on the other hand, I could help someone with all day and all night.