Derivative question,help needed.

[machine gewehr]

Find the derivative of the function given implicitly as

y^3 = 2x^2 + 2xy


I have no one to ask questions and I can't be sure of my solution. please.

Also,I'd apreciate a step by step solution much more.Promise,next time you're in Istanbul,beer's on me.

[Jim Nazium]

Yikes, it's been a while, but I think you just have to differentiate both sides of the equation and then solve.

Left side: d/dx(y^3) = 3y^2 dy/dx
Right side: d/dx(2x^2 + 2xy) = 4x + 2x dy/dx + 2y
now solve 3y^2 dy/dx = 4x + 2x dy/dx + 2y
to get dy/dx = (2y + 4x) / (3y^2 - 2x)

[D Rokk]

my ex is a math teacher.. let me email her..

[Chebass88]

Originally Posted by Jim Nazium

Yikes, it's been a while, but I think you just have to differentiate both sides of the equation and then solve.

Left side: d/dx(y^3) = 3y^2 dy/dx
Right side: d/dx(2x^2 + 2xy) = 4x + 2x dy/dx + 2y
now solve 3y^2 dy/dx = 4x + 2x dy/dx + 2y
to get dy/dx = (2y + 4x) / (3y^2 - 2x)

This is correct, assuming that you are required to differentiate with respect to x.

[machine gewehr]

Thank you so much!

Now,let me send you the 4 pdf files that each has 10 questions.

[bongomania]

Funny, I'm doing the same level of derivatives right now in Calc class.

[Chebass88]

Originally Posted by machine gewehr

Thank you so much!

Now,let me send you the 4 pdf files that each has 10 questions.

Only if you sent a money order for $3.00 per question!

ian

[machine gewehr]

Originally Posted by Chebass88

Only if you sent a money order for $3.00 per question!

ian

And you're saying this 4 days after the exam?