3PDT Wiring

[JehuJava]

I've noticed a few different ways to wire a 3PDT switch. Are there any benefits for using one way or another?

I have also seen the LED resistor on either the + or - lead...is either acceptable?



or



or

[Darkglass]

Hey man! The first diagram has what is called a "shunt connection". It takes the circuit's input to ground when the pedal is bypassed, this is useful in cases of oscillation when bypassed (this may occur with very high gain pedals at low volumes).
If is not the case, then it won't make much of a difference which one you use (having in mind that the second is much easier to do)

Best Regards!

Doug.

[JehuJava]

Thanks for the info Doug. Is there a case when using the shunt wired 3PDT would be bad? Too me, #2 seems the easiest. But since I'm just starting out #1 and #2 are probably both difficult at first, so I may as well "specialize" in the one that may help with potential problems down the road.

What do you think about the resistor on the LED? What is the difference between connecting it to the + or to the -?

[Darkglass]

Originally Posted by JehuJava

Thanks for the info Doug. Is there a case when using the shunt wired 3PDT would be bad? Too me, #2 seems the easiest. But since I'm just starting out #1 and #2 are probably both difficult at first, so I may as well "specialize" in the one that may help with potential problems down the road.

What do you think about the resistor on the LED? What is the difference between connecting it to the + or to the -?

Hey! No problemo .
I can't come up with any case in which using the shunt connection would be counterproductive. The resistor must be connected to either pin of the LED in order to limit the current (if you don't, you'll probably burn it).
There's no electrical difference between commutating + or - to control the LED, all though if you want to shunt the effect's input, you must do so by using the - (ground).

Regards!

Doug.

[JehuJava]

Awesome news!

[cheapbasslovin]

Just want to add that 1 and 3 are pretty much the same method. There are a few minor differences on the specific locations of points to be wired, but on an electrical schematic they would be nearly identical and function as though identical.



I hold all of the above to be true unless my eyes or my brains let me down (again ).

[JehuJava]

I kinda thought so...I see where both the PCB inputs go to ground. Thinking about what Doug said about the resistor being on the LED's ground when sending the PCB input to ground...shouldn't #3's resistor be on the LED's ground as well?

Here's were I wish I had an EE sitting next to me while I try to decipher schematics and theory.

[cheapbasslovin]

The resistor will reduce current no matter which side of the LED it is on. If electricity is water, the LED is a turbine generator, and the resistor is a valve in a fixed position reducing flow. In water, the valve will reduce flow no matter which side of the generator it is on, and in a circuit as simple as this, a resistor will do just the same.