Dry out on the Micro POG is "buffered". ¿Que?

[3toes]

What exactly does that mean? And furthermore, would I run into any problems trying to split that buffered dry signal?

[Bryan R. Tyler]

It means your signal will pass through a transistor or op amp rather than being wired from the input straight to the output. They usually need your pedal to have power to work.

Here's a Googled answer for you:
http://www.geofex.com/article_folders/bypass/bypass.htm

[3toes]

Originally Posted by Bryan R. Tyler

It means your signal will pass through a transistor or op amp rather than being wired from the input straight to the output. They usually need your pedal to have power to work.

Here's a Googled answer for you:
http://www.geofex.com/article_folders/bypass/bypass.htm

Thanks Bryan

By the way, I have an awesome new diagram should you want to see it... I think this one is gonna be the golden ticket

[Bryan R. Tyler]

Bring on the confusion!

[3toes]

Originally Posted by Bryan R. Tyler

Bring on the confusion!

Actually it's much simpler now! Instead of splitting the Dry out of the POG, I figure I should split the direct signal BEFORE the POG



So it's like a Bi-amp setup, except they're ultimately going to the same amp Just think of Loop 1 as the first amp, always clean. And the rest of the effects are in line for amp #2.