Originally Posted by Baddassbassist
I have a Hartke HA2000. Both speaker output jacks say 8ohms. The manual says you can get 200 watts at 4ohms. I have a single 4X10 Bass cab rated at 4ohms - 1,200 watts peak & single 15" bass cab rated at 8ohms - 1,400 watts peak.
I want to use both cabs and get the full 200 watts out of my Hartke HA2000 head. How do I do that? Thanks for your help.
You can't! (using both cabs)
That amp can only handle a 4-ohm speaker load at a minimum (anything higher is fine, but you can't go lower). The two outputs are wired in parallel (they are connected to each other inside the amp). So, you have the following choices:
1. Plug your 4-ohm cab into one of the outputs. This will provide a 4-ohm load (which is the minimum load) for this amp. In this scenario, you have to leave the other output jack empty. This would provide 200 watts of power into your 4x10 cab.
2. Plug your 8-ohm cab into one of the outputs. This will provide an easier load (an 8-ohm load) for this amp, but you will only be getting about 150 watts out of your amp. Your amp will run a bit cooler in this configuration.
3. Sell your 4-ohm cab and replace it with an 8-ohm cab, and then plug two 8-ohm cabs into the amp. This will provide a 4-ohm load and give you 200 watts of power.
Do not plug your 4-ohm cab *AND* your 8-ohm cab into the back of this amp, because that would result in a 2.67 ohm load, which is too low (not enough impedance) for that amp, which would harm the amp (it would overheat).
Daisy chaining your two cabs (amp to cab to cab) would be exactly the same as plugging both cabs directly into the back of your amp (because the outputs are wired in parallel), so don't do that, as that would be a 2.67 ohm speaker load.
Hope that helps.