Discussion in 'Amps [BG]' started by dvdsk8, Apr 3, 2014.
Hello someone knows if a Cabinet aguilar DB2x12 into 4 ohms can be modifiable to 8ohms?
Only by changing the speakers. No rewiring option can change any 4ohm cab to 8ohm or vice versa.
Your enclosure must have 2 x 8 ohm speakers wired in parallel, which makes it a 4 ohm cabinet.
If you would wire the two speakers in series, the cabinet would have 16 ohm.
Hope that helps,
Another idea: if you want to change the impedance of the cabinet, I guess you want to combine it with another cabinet and you want to connect both to an amplifier, which can't go under 4 ohm in total.
If that is the case, there is another solution. If you have two 4 ohm cabinets for example, you can build a special cable (you don't have to open the cabinets or change anything within the cabinets) that puts both cabinets into series. For example I have two 4 Ohm Yamaha cabinets connected to one Markbass Amp LMII. With the cable solution the two cabinets result in an impedance of 8 ohm. If you combine a 4 ohm and a 8 ohm cabinet you get about 12 ohm. This means less power from the amp, but more speaker-surface.
4 and 8 parallel:
Rges=R1 * R2 / R1 + R2
4*8 / 4+8 =2,666
in series: 12 ohm
In my case the Yamaha cabinets both have only one 10" speaker but I guess it works the same way, if the cabinets have 2 speakers and you put the cabinets into series (not the single speakers within the cabinets). But I'm not an electronics-expert so I'm not 100% sure, if it really doesn't matter or has disadvantages.
Putting loudspeakers in series isn't a good idea (there are several reasons for that). If they are exactly the same it's no problem.
Besides that, putting a 4ohm cab in series with an 8 ohm will give you a nominal impedance of 12ohms.
Why isn't it a good idea and what are the reasons? And aren't most 2 speaker cabinets that are 8 ohm just two 4 ohm speakers in series? Your first sentence sounds as if it's always a problem and never a good idea, then you write just the opposite "No Problem"???
4 ohm + 8 ohm in series makes 12 ohm is exactly what I wrote in the post above.
If the cabinets each have a crossover they can interact poorly when in series. An 8Ω cabinet in series with a 4Ω cabinet will mean that the 8Ω cabinet will get twice the power going to the 4Ω.
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