I ought to know how to do this, but I've got "old man's brain" today... So, I've got 2 points on a circle, and the distance between them, and also the distance from that line to the circle at the mid-point of the line. How do I determine the radius of the circle? Drawing a blank...

I used-to-was-kinda smart, but yeah, anyone else remember reading "Flowers for Algernon"? The moment the human subject (now genius level) discovers the test rat's "rat genius" results aren't permanent and are fading away? Yeah, that's me. i know I'm losing it...

I scored 100 on the NY State Geometry Regents exam in 10th grade, and got a max rating "5" in AP Calc, so it should be easy. But... hehe... Realized I have 3 points, the two ends and the midpoint, that's enough, now something about them all being equidistant from the center of the circle... some something squared and then a square root something hehe

Intersecting chords theorem: Calculate the radius of a circle given the chord length and height of a segment See also a calculator here: https://www.vcalc.com/wiki/vcalc/radius-of-circle-from-chord-length-and-arc-height

AP Calc in high school and a math minor as an undergrad. But, in the nearly 40 years since then, all I’ve used is some basic statistics. I got nothin’.

Ah! Intuitively obvious to even the most casual reader! It's about 8.92"!! Thanks! Off to find a 9" radius sanding block!! hehe

Mechanical Engineering degree and have a math minor. Haven’t used anything beyond single variable algebra since the last exam.

I made a mistake in my post above, and posted the same link twice. I meant the second link to be this calculator: https://www.vcalc.com/wiki/vcalc/radius-of-circle-from-chord-length-and-arc-height I did take the liberty to edit my earlier post to reflect what I had intended it to say. Sorry.

You can’t draw a straight line in old basses without referencing the parallel equivalence of p-bass pickups vs the greatness of tone. I also didn’t see anything divided by entwistle/pino + budget. Good luck.

I believe it as simple as: C = distance between points (chord length) D = distance from center of line to circle center R = radius You have a right triangle where the hypotenuse is R, and the other two sides are C/2 and D. So, R**2 = (C/2)**2 + D**2 Take square root of both sides and: R = sqrt((C/2)**2 + D**2)

Wow. I took algebra up through grade 12 (starting slinking away from math at the sight of calculus) and I don't recall ever hearing about "chord lengths"! Maybe they're called something different in Canada?