so I have an svt2. Currently, I have 3 ampeg cabinets. 210(8 ohm), 115(8ohm), and 410hlf(4ohms). Couldn't I connect the 15 and the 10's to one speaker jack for a load of 4 ohms and connect the 410 to the other speaker jack? Wouldn't this result in an overall load of 2 ohms? I have no idea why I would ever need this setup but I just want to know. On the other hand, maybe I'll just sell them all and buy a berg cab.
If you connect 8ohm cab to another 8ohm cab and then to speaker jack, you won't get 4ohms but 16ohms. There is a difference between series and parallel connections. Series: i=i1+i2+... Parallel: i=1/i1+1/i2+... "i" is a total impedance, "i1" and "i2", etc. are cabs impedance. am I thinking right?
You got the series parallel concept down, but probably 98% of speaker cabs piggy back connections are parallel, not series.
Connecting the two 8 ohm cabs through their paired inputs would be a parallel connection in the vast majority of cases, not a series connection.
I've never seen a commercially built amp or cab with a series connection. They're parallel. Hence, 2 ohm load in your case. BTW it really doesn't matter exactly where the piggy back is located. For instance you could connect your 4 ohm and 8 ohm cab together, and use the other jack for the other 8 ohm cab. The end result would be the same.
Nemesis does it. The old 210 combo was wired for 4 ohms to get 200w output, and if you hooked up an ext. cab, it dropped to 8 ohms and cut the power.
If you connect the cabs in this manner you are connecting them in parallel. This misconception that daisy chaining cabinets together is wiring them in series seems to be rampant around here. It's not. Also, your second equation is wrong, it should read 1/i = 1/i1 + 1/i2 + ...
But not on unpowered cabs; just on some combo heads. For the OP: Remember when connecting multiple cabinets that the total power from the amp will be distributed among the cabinets. 4-ohm cab: 1/2 the total power 8-ohm cab: 1/4 the total power 8-ohm cab: 1/4 the total power Be careful not to fry the 4-ohm cab.