Legion Sound 8x10 re wire

Discussion in 'Amps and Cabs [BG]' started by lowlyneo, Jul 8, 2013.

  1. lowlyneo


    Jul 8, 2013
    Hello all. I am very new to this forum but this is my last ditch effort to get information. I have a Legion Sound 8x10 I believe the model number is "emi-810". I bought it from a friend who had gutted the cabinet to rewire and never got around to it. So now I have the wiring hanging inside and I have 8 8ohm subwoofers and Horn to wire. Also the rear of the cab has two inputs. the backplate says its rated for 1200watts or 2400watts RMS. I have no idea how to wire the cabinet or why there are two inputs in the back. I will be posting pictures in a few days.
  2. lowlyneo


    Jul 8, 2013
    Impedance- 4ohm
    RMS Power- 1200 watts
    Peak- 2400 watts

    is what the backplate reads
  3. I'm not to sure how the wiring on horns works, I'm sure someone will chime in on that. You'll need to wire the speakers as two groups. The top four speakers wire in parallel, and do the same for the bottom four. This gives you two groups with resistance of 2 ohms. You'll then wire the two groups in series to make it 4 ohms.

    The two 'inputs' is actually an input and output which are wired in parallel to send power to another cabinet.
  4. lowlyneo


    Jul 8, 2013
    Thank you so much for the quick response, Also does it matter which jack you use as an input, they aren't labeled. Im assuming the one that has the resistor on it would be the one to use? Now to wait till someone knows how to wire the horn in.
  5. TheRealKong


    Mar 17, 2011
    If you wire the two jacks in parallel, than it does not matter at all, which jack you use for input.

    Is there a highpass for the Tweeter / horn? There should be one. If not you are allowed to wire the horn in parallel to one of the jacks.


  6. flatfender

    flatfender Ad eundum quo nemo ante iit

    If its a piezo tweeter you don't need a crossover and you just wire it directly to the speaker wires.
  7. lowlyneo


    Jul 8, 2013
    Im not sure what that means, but if your talking about the resistor type object that is between one of the wires and the input jack then yes its there. How would I wire it with one of these highpass things? I only say "resistor type" because it resembles that, a thick resistor.
  8. lowlyneo


    Jul 8, 2013
    So would this be the correct way to wire this? given all speakers are 8 ohms

  9. 1958Bassman


    Oct 20, 2007
    That would blow your amp unless it's designed for a 1 Ohm load.

    Do this for each group of four speakers and wire the two sets parallel, before connecting the + and - to the jacks.

    This configuration makes an 8 Ohm load for each group of four speakers.

    If you use an amp that only handles an 8 Ohm load and has one output jack, DO NOT connect it to all of the speakers by using a Y cord- the 4 Ohm load won't make your amp happy. If it's a tube amp, it may have a separate 4 Ohm output, so this would be OK. If the amp has two 8 Ohm output jacks, connect one output jack to each input jack and DO NOT make any connection between the jacks on the cabinet.

    What amp are you using?

    FYI- if one jack is for input and one if for output, it's for sending signal to another cabinet, not power. Power is just a calculated value. Only connect it that way if you know your amp can handle the additional load.

    Also, that "big, thick resistor" is probably a capacitor, used to filter the mids/bass from the signal going to the horn. Leave it in place- it helps a lot.
  10. lowlyneo


    Jul 8, 2013
    I was basing my diagram from ridethespirals response to my question. I am trying to achieve 4 ohms total. and there is one input and one output jack including a horn with an in line capacitor 8 8 ohm speakers. I guess im a little confused now, do I wire both groups in parallel and then run them in series or run each group in series and then in parallel or vise versa. so confused :\
  11. lowlyneo


    Jul 8, 2013
    so is this more correct?

  12. 1958Bassman


    Oct 20, 2007
    No- copy the diagram in the link. Each pair of speakers in series will show 16 Ohms. Wired parallel with the second pair, it drops to 8 Ohms. The second group of four speakers will also be 8 Ohms and wired parallel to the first group of four, the result will be 4 Ohms. Wiring in series, the "impedance" of each speaker is added. This applies to any speakers in the circuit and the impedance of each doesn't matter- you would calculate this by simply adding the numbers. You would wire two speakers in series by connecting the wire from the jack's + to the first speaker's + terminal and then, connect from the first speaker's - terminal to the second speaker's + terminal. Connect the second speaker's negative terminal to the jack's - terminal.

    Parallel is trickier- The easy way to calculate the impedance of two speakers is by multiplying the two numbers and dividing that by the sum of the two numbers. If they're both 8 Ohms, you use (8 x 8)/(8+8), or 64/16, which comes to 4 Ohms. If one is 8 Ohms and the other is 4 Ohms, you'll have (8 x 4)/(8+4), or 32/12=2.67 and you may see this formula stated as "product divided by the sum" or "product over sum".

    If you have doubts about getting this to work by yourself, you could go to a car stereo shop- they SHOULD be able to wire this easily- they work with series/parallel speaker loads all the time.
  13. 1958Bassman


    Oct 20, 2007
    Here's a way to do this- I'll label the speakers, from top to bottom, L1 (top left), L2, L3, L4 (bottom left) and R1 (top right), R2, R3 and R4 (bottom right).

    Put a piece of two conductor speaker wire on each speaker that's long enough to go to the jacks and cut another piece, to be used later. Connect the (-) of L1 to the (+) of L2 and the (-) of R1 to the (+) of R2. Connect the two remaining (+) wires together and do the same with the remaining two (-) wires. Repeat this with L3/L4 & R3/R4 and their remaining wires. Then, combine the paired (+) wires with one end of the spare piece's (+) wire and combine the paired (-) wires with one end of the spare piece's (-) wire. Connect this wire to the jack.

    L1/L2 = 16 Ohms, R1/R2 = 16 Ohms and these pairs wired parallel = 8 Ohms (16 x 16)/(16+16)= 256/32=8 and again, wiring the two four speaker groups parallel will result in a 4 Ohm load.

    Hopefully, this image will help- my drafting program is messed up, so I had to use Paint.
  14. will33


    May 22, 2006
    Imagine the cab as a pair of 8ohm 410's. Wire each group of 4 in series/parallel, then wire the 2 groups in parallel, just as if you were stacking two 410's to make one 810.

    If your part is in fact a resistor, then your HF horn is a piezo. Make sure the resistor is in line with the + wire going to the horn. If it's a capacitor, then your HF horn is a regular diaphram/coil driver. Make sure the capacitor is in line with the + wire going to the horn.

    Actually, it doesn't even matter if you know what that part is, just put in line with the + wire going to the horn.
  15. lowlyneo


    Jul 8, 2013
    ok I understand. Just so I can be absolutely sure could you repost that picture in a higher resolution? its very small and I can't tell were the + and - leads are Im assuming that on every speaker the + lead in the diagram is on the top and the - is on the bottom. Also the input jack's + lead is on the left and the - is on the right? Im only asking because this part of the description is a little confusing "Then, combine the paired (+) wires with one end of the spare piece's (+) wire and combine the paired (-) wires with one end of the spare piece's (-) wire. Connect this wire to the jack." Sorry for the ignorance on my part, I've never wired a speaker cabinet.
  16. lowlyneo


    Jul 8, 2013
    I just want to say thanks for all the replies and all of the info. I'll be wiring it up in the next couple of days here.
  17. edit: removed due to incorrect diagram :rollno:
  18. INTP


    Nov 28, 2003
    Dallas, TX
    I'm pretty sure that this will five you 16 ohms at the jack, not 4 ohms.
  19. The hand-drawn diagram is two series-wired sets of four 8 ohm speakers in parallel to each other for a total impedance of 16 ohms. What you want is two parallel-wired sets of of four speakers and the sets in series to each other.
  20. Oh crap! Good catch. I don't know why I was thinking they were 2 ohm speakers. I'll re do the diagram once I'm home!