I know there is a huge thread containing links to all sorts of things covering ohms, but I couldn't find an answer to this. If you're daisy chaining two cabs together, do you add the impedences as you would resistors in a series (a 4 ohm extension to an 8 ohm cab would be 12 total ohms) and then use that new value in the impedence formula, being 1/n = (1/a + 1/b + 1/c ...)? Ex. A stack has three cabs. Two 8 ohm cabs are wired normally (in parallel) and one has a 4 ohm cab daisy chained to it. 1/n = 1/8 + 1/b b = 8 + 4 = 12 1/n = 1/8 + 1/12 1/n = 5/24 n = 4.8 ohms Is that correct?