# Swr 4x10 8 Ohm to 4 ohms

Discussion in 'Amps and Cabs [BG]' started by Nighttrain1127, Mar 19, 2005.

1. ### Nighttrain1127Supporting Member

Nov 27, 2004
Near Worcester MA
I have a Swr workingmans 4x10 that is eight ohms. I want to rewire it to 4 ohms but it all runs together into one input not a regular harness . how would I go about changing this Without chopping up the wiring harness if possible?

2. ### Mudbass

You can't, the math doesn't work out. Your cab has four 8ohm drivers in it (most likely) and there's no way to wire four 8ohm drivers to equal 4ohms.

3. ### JSCHRO7376Commercial User

Feb 23, 2004
Los Angeles County, CA
Owner, Schroeder Cabinets
+1

You have to get 4 new speakers with a 16 ohm impedance each to achieve a 4 ohm cabinet; re wiring won't work.

4. ### illidian

Jul 2, 2004
He could do it.

FOUR x EIGHT ohm SPEAKERS
Parellel series (four plus four is eight for parellel, two eights in series is four).

FOUR x SIXTEEN ohm SPEAKERS
Parellel (sixteen divided py two [for one couple of speakers] is eight, wired in parellel with another eight would be four ohms).

FOUR x FOUR ohms SPEAKERS
Series parellel (four divided by two is two, two and two wired in series is four).

Perfectly possible.

[size=small]Disclaimer: technical names of "series" and "parellel" may be mixed up[/size]

5. ### MuzikMan

I'm sorry to point this out but I gotta do it. Four plus Four? These are eight ohm speakers, not four!

Sorry, nice try!

6. ### MuzikMan

By the way parallell/series and series/parallel would produce the same results with four drivers.

7. ### pdxmar

Feb 13, 2005
you need to find the impedence of the speeakers......usually some combination of series and or parallel will get the desired result with 4 speakers. If they are all 8 ohm speakers getting a 4 ohm load is not possible......2 ohm is no problem however.

8. ### illidian

Jul 2, 2004
Figures, my math was right but I get caught when I don't proofread.

Let's try that again...

FOUR x EIGHT ohm SPEAKERS
I believe people have said it's not possible. If I'm wrong then someone can do the math for me.

9. ### ironfist

Feb 5, 2000
If you have an 8 ohm 4x10 cabinet with four individual drivers each with an 8 ohm impedance (most likely by far), than it cannot be wired to be a single enclosure with a nominal 4 ohm rating.

The cab is wired in series/parallel. Each pair of speakers is wired in series, then the two pairs are wired together in parallel (or vice versa). This gives you a nominal load of 8 ohms.

If you wired the whole thing up in series, you'd have a cab with a nominal impedance of 32 ohms.

If you wired the whole thing up in parallel, you'd have a cab at 2 ohms.

The only exception would be two wire two of the speakers in parallel and leave the other two unhooked. That would give you four ohms.

10. ### MuzikMan

Well lets see. Assuming 8 ohm drivers:

All series. 8+8+8+8=32
All parallel. 1/(1/8+1/8+1/8+1/8)=2
Series/parallel 1/(1/8+1/8)+1/(1/8+1/8)=8

11. ### Mark Reccord

No 4-driver 8-Ohm cabinet can be wired to be 4 Ohms without new drivers.
The only possible drivers for a 4-driver 8-Ohm cab are 2 Ohm, 8 Ohm or 32 Ohm and there isn't a combination of them that will result in 4 Ohms.