I have a Swr workingmans 4x10 that is eight ohms. I want to rewire it to 4 ohms but it all runs together into one input not a regular harness . how would I go about changing this Without chopping up the wiring harness if possible?

You can't, the math doesn't work out. Your cab has four 8ohm drivers in it (most likely) and there's no way to wire four 8ohm drivers to equal 4ohms.

+1 You have to get 4 new speakers with a 16 ohm impedance each to achieve a 4 ohm cabinet; re wiring won't work.

He could do it. What are the ratings of the speakers? If eight ohms, keep reading. If sixteen, skip to paragraph two. If four, skip to paragraph three. FOUR x EIGHT ohm SPEAKERS Parellel series (four plus four is eight for parellel, two eights in series is four). FOUR x SIXTEEN ohm SPEAKERS Parellel (sixteen divided py two [for one couple of speakers] is eight, wired in parellel with another eight would be four ohms). FOUR x FOUR ohms SPEAKERS Series parellel (four divided by two is two, two and two wired in series is four). Perfectly possible. [size=small]Disclaimer: technical names of "series" and "parellel" may be mixed up[/size]

I'm sorry to point this out but I gotta do it. Four plus Four? These are eight ohm speakers, not four! Sorry, nice try!

you need to find the impedence of the speeakers......usually some combination of series and or parallel will get the desired result with 4 speakers. If they are all 8 ohm speakers getting a 4 ohm load is not possible......2 ohm is no problem however.

Figures, my math was right but I get caught when I don't proofread. Let's try that again... FOUR x EIGHT ohm SPEAKERS I believe people have said it's not possible. If I'm wrong then someone can do the math for me.

If you have an 8 ohm 4x10 cabinet with four individual drivers each with an 8 ohm impedance (most likely by far), than it cannot be wired to be a single enclosure with a nominal 4 ohm rating. The cab is wired in series/parallel. Each pair of speakers is wired in series, then the two pairs are wired together in parallel (or vice versa). This gives you a nominal load of 8 ohms. If you wired the whole thing up in series, you'd have a cab with a nominal impedance of 32 ohms. If you wired the whole thing up in parallel, you'd have a cab at 2 ohms. The only exception would be two wire two of the speakers in parallel and leave the other two unhooked. That would give you four ohms.

Well lets see. Assuming 8 ohm drivers: All series. 8+8+8+8=32 All parallel. 1/(1/8+1/8+1/8+1/8)=2 Series/parallel 1/(1/8+1/8)+1/(1/8+1/8)=8

No 4-driver 8-Ohm cabinet can be wired to be 4 Ohms without new drivers. The only possible drivers for a 4-driver 8-Ohm cab are 2 Ohm, 8 Ohm or 32 Ohm and there isn't a combination of them that will result in 4 Ohms.