The old ohm question again

2.6 ohms, not happy for 4 ohm amp.

1/r¹ + 1/r² + etc = 1/Rtotal. Ohms maths.

 

Nope!
That head is 4 ohms minimum, anything lower will kill it.

Here is the quick and most commonly used answer sheet.

8 Ohm + 8 Ohm = 4 Ohms

8 Ohm + 4 Ohm = 2.67 Ohms

4 Ohm + 4 Ohm = 2 Ohms

 

If you connect two cabs in parallel with the same impedance just divide the impedance by two. For example if you have two 8 ohm cabs (8/2 = 4 ohms).

If you connect two cabs with different impedance in parallel, use this formula where Z is impedance:

for example if you have an 8 ohm cabinet and a 4 ohm cabinet.

 

This can be simplified for two impedances. Z1 X Z2 divided by Z1 + Z2. 4 X 8 =32 divided by 4 + 8 +12 2.67.

Or even simpler in terms of 8Ω impedances: 4Ω is two 8Ω loads. So 2x 8Ω and 8Ω is 3 8Ω loads. 8 divided by 3 is 2.67Ω.

 

reciprocal of ( reciprocal of 8 + reciprocal of 4) - بحث Google

 

You can do it that way if you like.

I prefer this formula because the form works with an infinite number of impedances:


For example, if you have three cabs just continue the sequence:



If I had three cabs with the same impedance I would simply divide the impedance by the number of cabs. For example 8/3 = 2.67 But this works as well:



Or if the impedances are dissimilar



IMHO this formula maybe a bit more complicated, but I think is also a bit more universally applicable.

One caveat...I use a calculator .

 

I just use my brain! LOL

 

Rise up bassists! Resist Ohm's law!
I have a resistance to properly using "impedance".

 

Mind if I use yours too... mine doesn't seem to be working lately...

 

Are you sure your SWR 210 is 4 Ohm?

 

Apart from the ohms issue, I'd suggest getting two 8-ohm 2x10s rather than a 2x10 + a 1x15. Stack'em vertically and you'll have a killer rig. (I have two such rigs, one of which is SWR's.)

 

They did make them in both 4 and 8 ohm, but it wouldn't hurt to test it. It's pretty easy to blow up a 4 ohm 210 so could easily be reloaded at 8 ohm.

Multimeter on Ohms low range. Should show about 3ohm if it's a 4 ohm cab and 5 to 6 ohm for an 8 ohm cab.

 

4 ohms in parallel with anything is less than 4 ohms. If your amplifier can’t support a load smaller than 4 ohms, you cannot do it.

 

If you open up the 210 you might be able to change the impedance. It may have two 8 ohm drivers in parallel to get to 4 ohms together. Wiring them in series would make the cab 16 ohms which you could then safely combine with the 8 ohm cab.

Note however that two cabs with different impedance will not be equally loud.

 

Speakers in parallel add conductance. You get conductance (which is in mhos) by taking the reciprocal of the impedance. An 8 ohm cabinet has 1/8th of a mho of conductance, a 4 ohm one has 1/4th of a mho. So, for a 4 and 8 ohm in parallel, you add the conductances - .125 plus .25 equals .375 (or 3/8ths). To convert it back to ohms, take the inverse of that sum - 3/8 mhos is the same as 8/3 ohms, or 2 and 2/3rds ohms, or 2.67 ohms.

 

Or just review the sticky on this forum so we don't have the to call up the math again to the old ohms "homage".

 

Yeah, some smarty pants thought it would be fun to spell Ohm’s name backwards for the inverse. Flammable - inflammable, sine - cosine, Ohms - Siemens, chocolate - vanilla, salt - pepper, bassist - drummer.