Dismiss Notice

Psst... Ready to join TalkBass and start posting, make new friends, sell your gear, and more?  Register your free account in 30 seconds.

Wiring cabs in series....

Discussion in 'Amps and Cabs [BG]' started by lukaas, Jul 2, 2003.


  1. ok. I worked through ohms law and decided not to run my tl box(15" 8ohm) and my Marshall 210 (4ohms) in parallel, it will stress my fender BXR 300......

    If i wanted to run them both could I run them wired in series?

    If so how do I do this,

    Thanks for any insights you might have!
     
  2. ESP-LTD

    ESP-LTD

    Sep 9, 2001
    Idaho
  3. zombywoof5050

    zombywoof5050

    Dec 20, 2001
    Here's a diagram of a cable that will connect your amp to two speakers with the speakers connected in series:
     
  4. That is a great diagram! I've got a cable just like that. Be to connect the two 1/4's that go into your speakers [hot to cold] (just like the picture) if you wire [hot to hot] and [cold to cold] (like parallel) your speakers will be out of phase.
     
  5. Cant say thanks enough......:D :D :
     
  6. Petebass

    Petebass

    Dec 22, 2002
    QLD Australia
    I have a question or 2. Wouldn't we then end up with a 12 Ohm load. How many watts does the BXR 300 deliver with a 12 ohm load? I wouldn't be much....

    Secondly, how would those watts be distributed. I mean if it was a standard parallel connection, the 4 ohm cab would get twice as many watts as the 8 ohm cab. Does that stay the same with a series connection?
     
  7. Good point. After doing all this wiring the amp probably won't have enough power to drive the speakers. It would be my guess that the (4ohm) 2x10's would recieve significantly more power than the (8ohm) 1x15. Basically what Pete and myself is saying is, "Yea it will work and won't overheat the amp, but, it may not be as loud as just running the 2x10's alone.":bawl:
     
  8. zombywoof5050

    zombywoof5050

    Dec 20, 2001
    True, the total impedence when running the 4 & 8 in series will be 12 ohms, so your amp will be delivering less power to them. And also true that the 4 ohm cab will be getting twice as much power as the 8 ohm cab.
     
  9. Actually, the 8 ohm cab will be getting twice the power that the 4 ohm cab will get. Power = I^2 * R, and since they are in series, I is the same through both. The one with the bigger R (8 in this case versus 4) will get the most power.

    If it was a standard hooking up in parallel, the 4 ohm would get twice the power that the 8 ohm got.

    If you hook up the series setup, you'll get 1/3 of the amp's max rated 4-ohm load power, and it will divide up as 33% to the 4-ohm cab and 66% to the 8 ohm cab.

    Chris
     
  10. zombywoof5050

    zombywoof5050

    Dec 20, 2001
    throbbinnut,
    You're absolutely right, I musta had a brainfart, so sorry for the misinformation.
     
  11. Thanks for all the input guys....to finish the story, I am selling the 210, upgrading the evtl box and doing a lot more practice!