No, I said nothing of the kind. I said the strings are not ground. You didn't explain why you think it is.
How did this conversation switch to strings? You said, "In a
bass you have one ground reference, at the output jack.
Nothing in the bass can be at a different potential."
Do you deny saying this? Anybody can go back and see it.
So, if a grounded bridge is at ground potential, which you
insist that it is, I can tie my pickup to it as, if you are right,
it will be as good as any ground in the bass.
That should be a clue to you right there; ground loop = two grounded systems connected together.
This brings us to the other problem with the arguments
against star grounding. Star (single-point) grounding is not
only to fight common-mode currents; it also establishes a
good ground for your signals. I think most of us would agree
that a grounded bridge would not be an appropriate ground
for a pickup or other bass components (although you keep
giving mixed answers as to whether it is ground or not).
Your bass has a single ground point at the output jack. Nothing is grounded until you plug in your bass to the grounded amp.
You're getting off on a tangent here (and I would say grasping
for straws to get out of this argument). Every bass has a
reference point for all of the signals within. This is the
definition of a ground. See
Wikipedia if you don't believe me.
When you plug in your bass, you are connecting your bass
ground to your amp ground.
Please demonstrate how the back of one pot is not at the same ground potential as another. Do you really think that a inch or two or wire will change that? It wont. You also can't measure any resistance in a short length of wire.
And it's not. Prove it is.
Unless your pots are perfect conductors connected with a
perfect conductor, there will be a voltage difference between
the two. As I already pointed out, there are induced noise
currents flowing everywhere within everything. Noisy guitars
(I'm sure you'll agree that they exist) are evidence of these
noise currents. Ohm's law (E = I * R) tells me that, if I have
current (I) and a non-zero resistance (R), I will have a
voltage (E). The conclusion is inescapable.
Furthermore, why are we restricting this debate to an inch or
two of wire between two pots? Let's go back to the more
intuitively obvious bridge connection. If you insist that there
is no potential difference, we should be able to connect the
pickup to the bridge. Is there anybody here who believes
that would be acceptable?
You started this post with a really dumb remark. You stated that the bridge/strings were ground. I'm sorry, but that kind of negates the rest of your argument.
I said no such thing. Please go back and reread. You are the
one who is insisting that there is no differences between
grounds in a bass. I pointed out that, if this were true, a
grounded bridge could serve as an adequate ground for any
component within the bass. I, of course, do not subscribe to
that notion.
If you want to demonstrate how two points several inches away from each other in the bass are at a different ground potential, then be my guest. Show us some real measurements, not conjecture.
Then give us a demonstration on how you can produce a ground loop. And I don't mean electrical field hash, I mean a real ground loop. One that produces a low frequency hum. You should also be able to measure that current flowing in the ground wire.
I already explained that noisy guitars are proof that stray
signals exist within guitars. Do you deny that noisy guitars
exist?
Also, the pickup to bridge connection example is not an
example of a ground loop; it is an example to demonstrate
a benefit of star grounding implementation -- one that
overcomes the essential fact that no two grounding points
are the same potential. The only way to overcome this
reality is to choose a single ground point.