I understand that two 8 ohm cabs makes 4 ohms and that kind of thing. But I've noticed headphones have pretty drastically different ohms. I've seen some that are very high priced that have a great deal more ohms than some cheaper ones. I want to say is 128 ohms vs like 32 or even 16 ohms. How does this work with amps, like does it directly translate to how loud your headphones are, or how much headroom, or both,?
I have some senheizer headphones. I don't know the ohms, but they really can't handle much without clipping. I have this origin effects pedal, two of them actually. One is the bass rig pedal, one is he Dx bass boost or whatever. To get the right sound out of them they have to be cranked up, and I already have my amp almost as low as it can go. So I'm trying to get new headphones to get more headroom. Will I be able to tell how much headroom they'll have by the ohms? And will open back headphones handle more power than closed back headphones? How else can I tell, like there are various specs, there's the dB range, the size of the driver, the ohms, open/closed, type of driver such as neodymium or planar headphones, etc. I am trying to upgrade from senheizer BT450 headphones.
Any advice would be appreciated.
I have some senheizer headphones. I don't know the ohms, but they really can't handle much without clipping. I have this origin effects pedal, two of them actually. One is the bass rig pedal, one is he Dx bass boost or whatever. To get the right sound out of them they have to be cranked up, and I already have my amp almost as low as it can go. So I'm trying to get new headphones to get more headroom. Will I be able to tell how much headroom they'll have by the ohms? And will open back headphones handle more power than closed back headphones? How else can I tell, like there are various specs, there's the dB range, the size of the driver, the ohms, open/closed, type of driver such as neodymium or planar headphones, etc. I am trying to upgrade from senheizer BT450 headphones.
Any advice would be appreciated.