Parallel - Series multiple cab HELP !

[RockFistMusic]

I need clarification

When you have 2 cabs, say a 410 rated 800w @ 4 ohms and then a 115 rated 400w @ 8 ohms - each has 2 neutrik connections on the back, and I go from my bridged amplifier output into 'first' cab, then connect the 2 cabs with another neutrik cable -

While I have the calculator that tells me the net ohm load, does it matter which cab goes 'first' and which is jumped to from the 'first' cab ??

I heard there may be a case where the 'first' or 'second' cab get more wattage/load than the other, is this true and how ?
If the case, I want to be sure to put the higher rated cab in that spot.


** standard 2 pin Neutrik connectors on all

THANKS





Eden, GK, Genz, Fender, Ampeg, SWR

 

[B-string]

First DON'T DO THIS. The in and out on cabs are parallel connections so your net load will be 2.67 ohms. A bridged amp would have to be 1 ohm stable per side to accept this load. Which cab you hook up first will not matter at all.

 

[Jazz Ad]

Also, the 4 ohms cab will get twice as much power as the 8 ohms, no matter which order you plug them.
Leave your amp unbridged and use 1 cab per side. This is safe and will allow you do send different levels into each cab.

 

[BassmanPaul]

Ditch the 1x15 - it will always be a weak link.

 

[RockFistMusic]

My amp has 2ohms bridged

??

 

[B-string]

My amp has 2ohms bridged

??

What amp are you using? I have not seen an amp that will bridge two amp modules to a 2 ohm load?

 

[RS66LB]

My amp has 2ohms bridged

??

...are you using a Crest 10001? -one of the few amps that easily run 1 ohm stereo and don't have an issue with 2 ohms bridged

 

[B-string]

Read your specs! It is rated for 2 ohm loads per side in dual mono, only down to 4 ohms in bridged (per the Carvin web site).

"BX1500 Features:

- 2 power amps deliver 300w at 8 ohm, 450w at 4 ohms, and 750w at 2 ohm each or 900w at 8 ohm bridged or 1500w at 4 ohms bridged"

 

[RockFistMusic]

Yea sorry my bad on that typo, point is assume we only get to a net 4ohm load

does it matter which cab goes first in line or second? Assume they;re both 8ohm cabs going into a new 4 ohm on the bridged output....

 

[the mojo hobo]

Instead of bridging connect one cab to each of the Carvin's outputs. You can then control the volume of each cab separately and you have no worries about impedance.

BTW the Carvin will not do 2 ohms bridged.

 

[dmac1961]

While some amps are "stable" at two ohms bridged, it is not recommended for sustained use. Distortion goes up (not the good kind), and excessive heat can be generated, not to mention overpowering your mismatched components.

 

[RockFistMusic]

OK , let me try it this way FORGET THE CARVIN

I have an Ampeg SVT-8pro rated stable at 2 ohms
Regardless if I even get to the 2ohms or not, the questions is as follows

I have a 410 @ 8ohms
I have a 115 @ 8ohms

I am jumping them together and the net would of course be 4 ohms, BUT my goal is to make sure the 410 gets the most wattage if that is possible....

???

Thanks guys

 

[dmac1961]

The only way to ensure that is a separate power amp channel for each cab.

 

[the mojo hobo]

If they are both 8 ohms that will split the power evenly. If one is 4 ohms and the other 8 ohms, the 4 ohm cab will get more power than the 8 ohm cab.

 

[the mojo hobo]

The only way to ensure that is a separate power amp channel for each cab.

Which the Carvin does.

 

[RockFistMusic]

Reason I ask is of course knowing which cab you want to get the lion's share of power , but I have heard conflicting reports where one says the first cab gets more and another actually states the second cab gets more

On the SVT it has 2 outs and if I ever used cabs of different ohms I would parallel them on one output since I do know varying loads on the amps main outs is not a good thing

and Thanks Mojo

 

[the mojo hobo]

It doesn't matter which goes first as long as the speaker cable is heavy enough to handle all the power. It is always best to connect each cab to the amplifier individually.

 

[B-string]

There is no "magic" here to be had. To use the abused "water analogy" the cab with the least resistance to flow (4 ohm) will get the most flow, the 8 ohm has more resistance to flow so less flow. Even though we are talking impedance not resistance to flow (AC impedance, resistance is DC) the principal remains. If you have two cabs with the same resistance they will receive the same power if you run individual speaker cables or "chain" from on cab to the other. The parallel connection in the cab is just like an extension of the connector at the amp.

 

[agedhorse]

Ditch the 1x15 - it will always be a weak link.

Not in this case, for the same signal voltage, the power balance will be just right.

Depending on the specific cabinets there may be no issue whatsoever, or it may not work all that well. The answer here is "it depends".

 

[agedhorse]

OK , let me try it this way FORGET THE CARVIN

I have an Ampeg SVT-8pro rated stable at 2 ohms
Regardless if I even get to the 2ohms or not, the questions is as follows

I have a 410 @ 8ohms
I have a 115 @ 8ohms

I am jumping them together and the net would of course be 4 ohms, BUT my goal is to make sure the 410 gets the most wattage if that is possible....

???

Thanks guys

This is different than your first example.

What is your real question? Define the question accurately and completely and you will get an accurate and complete answer.