I'm looking at changing one of my active EQ basses to passive, because most of the time when I play, I leave it flat and I just change the pickup switch. I was looking at installing a varitone kind of circuit (bandpass filter), but something that is stumping me is the hi-cut filter on the pickup.
It's an Ibanez ATK300/3EX1, and I've been using the ATK 100 wiring diagram as a reference point for the switch. This one, to be exact:
I see the capacitor there as a hi-cut filter, but when I look at the switch in my own ATK, it looks as if there is a resistor wired in what I believe to be parallel. If that's so, can I wire a potentiometer like a voltage divider, with a wire on the first lug, and a capacitor wired to the second lug, and have both of them meet on the switch, like a hi-cut filter that's adjustable? Or would I wire it like a conventional tone pot, where the common goes to the 2nd lug and then the capacitor is wired to the 3rd lug and soldered to the back of the pot and grounded?
It's an Ibanez ATK300/3EX1, and I've been using the ATK 100 wiring diagram as a reference point for the switch. This one, to be exact:
I see the capacitor there as a hi-cut filter, but when I look at the switch in my own ATK, it looks as if there is a resistor wired in what I believe to be parallel. If that's so, can I wire a potentiometer like a voltage divider, with a wire on the first lug, and a capacitor wired to the second lug, and have both of them meet on the switch, like a hi-cut filter that's adjustable? Or would I wire it like a conventional tone pot, where the common goes to the 2nd lug and then the capacitor is wired to the 3rd lug and soldered to the back of the pot and grounded?