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Or change/add one note and instead of Cdim use C mi7b5 and now you are implying a G7b9.
Eh..? Something went wrong here I guess or then I'm not following what you say. At least if you mean that Cm7b5/G = G7b9, because that's not true. Bdim/G = G7b9 and Bm7b5/G=G9.
OK -- figured it out. The tri tone inversion. A tri tone is the functioning interval of the 3rd and 7th in a Dom chord. The tri tone is also an interval where the 3rd and 7 can be flip-flopped. For instance C7 has a tri tone interval of E (3rd) & Bb (7th), which usually resolves to F (V7 > I). OR you can flip that interval and hear it as the 7th (E) and 3rd (A# [enharmonic of Bb]) of F#7 which usually resolves to B.... came across the prog G7 > c dim > D Maj... Don't have any theoretical reason to do this, but it sounds cool.
OK -- figured it out. The tri tone inversion. A tri tone is the functioning interval of the 3rd and 7th in a Dom chord. The tri tone is also an interval where the 3rd and 7 can be flip-flopped. For instance C7 has a tri tone interval of E (3rd) & Bb (7th), which usually resolves to F (V7 > I). OR you can flip that interval and hear it as the 7th (E) and 3rd (A# [enharmonic of Bb]) of F#7 which usually resolves to B.
This is done in modern music harmony and lays the ground for "tri-tone substitutions"; ala chromatic progressions as: d min > Db7b5* > C (ii - bII7b5 - I). *sub for G7 (ii - V7 - I)
So by flipping all the tri tones in a fully diminished chord as explained in the beginning of post #12, I have 4 more chords I can resolve to (actually 8 because they can be Maj or min) with roots D F A Cb