I have an Ampeg 610 Classic. If I were to replace the stock speakers with Weber 8ohm/ 20 watt speakers, how would I determine the final impedence/wattage?? I know it has to do with wiring parallel or in series, but I'm confused. Help??
#1 Why? (I'm not trying to be snippy, just curious) #2 Do you know the impedance of the stock speakers?
Total wattage is the sum of the six speakers' individual wattage (assuming they're correctly wired for equal power distribution). This will therefore be a miserable 120W. As important is the excursion limited power handling which is probably equally poor. Depending on your combination of series/parallel wiring the nominal impedance could be 48 ohms, 12 ohms, 5.3 ohms or 1.3 ohms. Why do you want to do this?!! Alex
relax relax relax. I just wanted figure out how the numbers added up, so I picked the first speaker that I knew the ohmage and wattage of. I am planning on swapping out the speakers in my cab. I think the structure of the 610 is quite punchy I just really want a crisper/sharper sound from the speakers. Im shopping around. Any suggestions?
Doing that is a matter of comparing the frequency response of the drivers you have now with that of other drivers that have suitable T/S specs for the cabinet. Finding out the frequency response and T/S specs of your current drivers will be the challenge.
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