Obvious answer is obvious.
Take the cash you would have wasted on stupid slot machines and get yourself some hookers and blow.
I would "like" that if it said "get yourself some good tequila and put the rest in the bank."
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Obvious answer is obvious.
Take the cash you would have wasted on stupid slot machines and get yourself some hookers and blow.
A nickle slot machine averages a 90% payout (you'll average a $90 win for every $100 you spend). Would your payout average half, double or stay the same if you spent the same amount of money playing two slot machines at the same time?
Ha ha ha. Just what do you need to be convinced?
Oh yeah two women playing multiple slots for hours does sort of negate the science.
Were they wearing their lucky socks?
What about tequila and a subscription to Brazzers?I would "like" that if it said "get yourself some good tequila and put the rest in the bank."![]()
Once more with conviction.I'm convinced. How many times do I need to say it?
your maths only applies to a simple series of two trials, so basically barking up the wrong tree in the wrong town as far as the OP question goes.Take this with a grain of salt, because I'm not very good with probability theory, but this is what I think to be correct.
Let X1 and X2 be two independent random variables, such that E(X1)=E(X2)=0.9 (Where E(X) denotes the expectation.) By a well known theorem from probability, we know that the expectation of a product of independent random variables is equal to the product of the expectations of the independent random variables. Hence, E(X1*X2)=E(X1)*E(X2)=(0.9)(0.9)=0.81.
So your expected payout is going to be $81.
Anyone want to correct me, if I'm wrong?
See, I would think the percentage would go down. Think of it this way. If I went out on six dates with one girl, my odds of getting lucky are like 90%. But if I went out on three dates each with two different girls, my odds of getting lucky are only about 50%. Putting in the time with one slot machine must increase the odds.