I did a search, couldn't find what I was looking for, it is bassically all in the title. On Fender styled basses, does getting a reversed headstock add tension to the low B string, or is it just a gimmick? Thanks for your time. 
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Here we go again!
For a given pitch/scale length/mass per metre combination, tension will be the same. BUT, and there is a but...
The lengths of string above the nut and below the saddle will affect how the string feels under your fingers and how it responds to bending (which includes stopping against the fingerboard or frets). Longer 'afterlengths' will make the string feel more compliant and less prone to sharpening in pitch when the string is deflected.
If you have access to an electric guitar with a locking nut, try this. Lock the nut and, using one of the strings whose peg is furthest from the nut, try to bend a note up a minor third. Notice how far you need to push the string. Now unlock the nut and do the same. You have to deflect a lot more to achieve the same minor third but the string will feel more flexible and compliant. Alternatively, do the same with a hard-tail and soft-tail Stratocaster - it is easier to achieve radical bends on the hard-tail but the strings feel slacker on the soft-tail even though they are not. Now try bending a minor third on the top and bottom strings and notice how far the string needs to be pushed to achieve the same interval - the big strings are far more sensitive to deflection than the thin ones. Which is why your correctly intonated bass has longer big strings than thin strings
If you don't have access to electric guitars (and why would you), you could try the same experiment comparing bending on the G strings of Fender and top-strung Musicman basses - the MM will yield greater change for a given deflection.
Why does this matter? As @Bruce Johnson alluded to above, even normal vibration of the string involves some deflection. Deflection = more tension. More tension = pitch sharpening. But as we have seen, the same deflection with a longer afterlength = less pitch change. Knowing that the pitch of big strings is more sensitive to deflection, it makes sense that longer afterlengths on the big strings will help maintain accurate pitch under deflection, even that required for normal fingering of notes.
So IME, reverse headstocks make perfect sense.
Zombie thread resurrection: I think understand the concepts @Bruce Johnson and @SteveCS detailed above, and agree that more snap on the lower pitch strings would be better.
However, I guess where I'm getting stuck is this: if you had a reverse inline headstock with exact balanced tensioned strings and plucked all of them with the exact same force, wouldn't the lower pitched strings move (flop) around more than if the you used a non-reversed inline headstock?
Well, yes, but "flop around more" isn't the way I'd describe it. The low B on a reversed headstock, with the extra length out beyond the nut, would swing slightly farther out to the side for the first couple of oscillations. But you'd barely be able to measure it. It would be a couple thousandths of an inch for a few milliseconds.
The Snap effect that I described above happens very quickly at the beginning of the note. It's the result of you pulling the string slightly farther off to the side, then releasing it. It builds up more speed as it crosses the centerline, after you let it go. But within a couple of cycles, it's back to oscillating the same as it would with the shorter outboard length and non-reversed headstock. The snap effect is a measureable lump at the beginning of the attack curve. A small increase in volume in the first few milliseconds of the note. Listening to it, that little extra snap at the beginning of the note makes it sound like the string is operating at higher tension/longer scale length. But it isn't. Adding the extra outboard length doesn't actually increase the tension. It changes the attack curve to make it sound like it has extra tension.