Concentric jazz pot wiring

[WillyW]

On the 250/500k 7ender potentiometer, which knob is the volume which is the tone? Which is the 250k, which is the 500k?

I’m using one outside of a jazz bass. (single pickup, single coil telecaster)

I need the 500k for my tone and the 250k for my volume… (am I thinking correctly)?

I can follow a wiring diagram but thinking outside that confuses me easily….

I ordered the pot and the plastic concentric knob direct from 7ender, and 10% off and then I had to order a sweet leather strap in order to get free shipping…

 

[LoveThatBass]

The top control is volume and the bottom tone

Yes, 250K volume and 500K tone. When wiring up from back side the tone is one closest to the pickguard and volume farthest away (bottom of the pot). This makes the volume top center control and the tone bottom ring on topside of pickguard.

 

[WillyW]

The top control is volume and the bottom tone

Yes, 250K volume and 500K tone. When wiring up from back side the tone is one closest to the pickguard and volume farthest away (bottom of the pot). This makes the volume top center control and the tone bottom ring on topside of pickguard.

Awesome thanks.

I'm also assuming usually a .022Uf cap would be used with the 500k tone and single coil?

 

[LoveThatBass]

That would probably work best.

 

[WillyW]

alright, so every concentric schematic I found was extremely unclear as to what was soldered to what, so I used a vol/tone schematic with separate pot and wired it accordionly.... after confirming which pot was the 500 and which was the 250k.

So I have a question for 62 Jazz players...

How the shag do you actuate that tiny little volume knob? I can't roll it with my pinky for love nor money...

the bottom tone knob is easy to roll...

I'll probably research what resistor I need to make the 500k pot a 250-300k and wire it so the bottom knob is the volume.... and use a .047uf cap....

 

[LoveThatBass]

500K with 500K in parallel (across the two outer wire lugs) equals 250K

 

[WillyW]

500K with 500K in parallel (across the two outer wire lugs) equals 250K

math is hard....

I'll look that up!

 

[LoveThatBass]

R1xR2/R1+R2

but basically two resistors of same value in parallel is equal to one half their value

 

[LoveThatBass]

750k resister across a 500k pot will lend 300k

 

[WillyW]

750k resister across a 500k pot will lend 300k

ok this I understand…

R1xR2/R1+R2

but basically two resistors of same value in parallel is equal to one half their value

I was to embarrassed to admit I have no clue what this says….

I thought R2D2 was having a conniption fit….

 

[LoveThatBass]

ok this I understand…



I was to embarrassed to admit I have no clue what this says….

I thought R2D2 was having a conniption fit….

Sorry, I thought I posted with that formula that 500K in parallel (tied across)with 500k comes to 250K.
I have had 42 years in electronics (now retired). No need to be embarrassed…just send R2D2 on it’s way