Geometry of Triangles

[JansenW]

The problem is not over yet:

The solution to the quadric is X = -6 or 4 which results in R = 65 (for X = -6) or 25 (for X = 4). The question now is "Which one is valid?" To find out you need to also solve for S and T using both values of X.

For X=-6, (R,S,T) = (65,220,-105)
For X=4, (R,S,T) = (25,80,75)

Since we do not live in a world with triangles with negative angles (-105), X must be 4 and therefore R = 25.

 

[jarrhead]

We got that, Jansen. I answered the problem, and I have done my homework.

I also now understand Quadratics.

 

[Bob Lee (QSC)]

It's been years since I took trig but couldn't you factor: 6x^2 + 12x -144 = 0 then solve for x?

I think you hit this with the quadratic equation.

 

[A-Step-Towards]

Or you could have some REAL fun and take it over to a drummers' forum .

i see what you did there and i laughed

 

[Fontaine]

x=4

edit...i only read the first page, I see you made it that far lol...my bad!

 

[Jimmy Bones]

Dude, most mathy I get is Pythagorus.