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Geometry of Triangles

OK i have been thinking about this i mean i just took a test on it use this formula below.

Your equation is 6x^2 + 12x - 144 = 0
a=6, b=12, and c=-144

now plug these numbers in where needed in the equation below. EDIT appears you got it another hmmm i dunno if this problem would work with these equation but i aint solving it for "fun" haha



tumblr_ktdwv9jgT11qzun0ko1_400.gif
 
OK i have been thinking about this i mean i just took a test on it use this formula below.

Your equation is 6x^2 + 12x - 144 = 0
a=6, b=12, and c=-144

now plug these numbers in where needed in the equation below. EDIT appears you got it another hmmm i dunno if this problem would work with these equation but i aint solving it for "fun" haha



tumblr_ktdwv9jgT11qzun0ko1_400.gif
that works but its quicker if you factorise it
 
Just realized you can factor out a 6 from the original equation and make it a LOT easier to factor. 6(x^2 + 2x - 24) = 0 should factor to (6)(x-4)(x+6)=0 making x = {-6,4}.

EDIT: Nevermind, looks like you guys have got it covered :)
 
A-Step, I think that's only for Quadratic Equations of Lines.

B being the y-intercept.
X being... well.. X
And I dont remember what a and c were, but I used to be really good at those.

Nah, it works for any quadratic equation (also, quadratic equations and linear equations are 2 seperate things). You may be thinking of y = mx + b, which is one form of a linear equation.

Wrong quadratics? No coordinates here, man. Just angle measurements. X is a value for part of an angle measurement

Not talkin' coordinates- {} brackets are used to discuss a set of values for x (in this case only 1 will apply since the other will make negative angle measures), while () parenthases are ordered pairs. I'm basically saying x = -6 and 4.