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GK Neo 410 High Range Attenuator on Full Mode question

#22
BassmanPaul said:
Pairing an 8Ω 2x10 with an 8Ω 4x10 is not a good idea. Both cabinets will be given the same amount of power split two ways in the 2x10 and four in the 4x10. The 2x10 will run out of excursion before the 4x10 even gets started. You could well have less available volume than the 4x10 by itself.
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im not positive about this but I don't think this is accurate.
when the two cabs are pluged into parallel outputs of the same amp the amp basicly sees them as a single 6x10 cab with a single 4 ohm load and gives all the drivers the same amount of power but with the 210 drivers having greater resistance they will simply draw less power from the source,...I think
 
#23
And, unfortunately you would be thinking wrongly. Trust me my post IS accurate!

Let's just play a bit with numbers. Your amp puts out say 800W. Each 8Ω cabinet will be given 400W. The 4x10 will spread that out as 100W per driver. The 2x10 will split the power two ways so 200W per driver. The drivers in the 2x10 are working with twice the power level of those in the 4x10.
 
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#24
but the power that is drawn by the driver is dictated by it's resistance as well not just by what the amp can put into the cab and drivers in a 8ohm 210 are going to have a different resistance than drivers in an 8ohm 410 cab and they will draw a different amount of power
 
#25
Sorry but wrong again.

Look at the 2x10 for example. With two drivers they must be either 4Ω wired in series or 16Ω wired in parallel to make an impedance of 8Ω. In either case the input power is shared equally between the two drivers.

Now the 4x10 would need drivers that are 8Ω each, wired series/parallel, or 32Ω (like the Ampeg 810) wired in parallel. Again the power is shared equally by all the drivers.

If you want a workable 6x10 from the specified configurations, you would need a 2x10 that has TWICE the impedance of the 4x10. Thus, as in your case, 8Ω 4x10 mated with a 16Ω 2x10 total system impedance will be 5.33Ω. The other choice would be an 8Ω 2x10 paired with a 4Ω 4x10 for 2.67Ω.
 
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#27
gpx1200 said:
but the power that is drawn by the driver is dictated by it's resistance.....
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Partially true but here's the problem: two CABS of equal impedance will draw the same amount of power each. If this is true, which it is, the drivers in the 210 cab are gonna draw twice as much each as the ones in the 410 will. So you have to double the impedance of the small cab in order to even things out.
 
#28
guess ill have to concede to the bigger brains on this one, I was looking at it kind of backwards.
but I have been running setups like this for a long time with no sound ishue or driver failure so I guess blissful ignorance works for me to.
 
#29
This conversation is incredibly helpful: thanks so much!

Outdoor gig—weather permitting—coming up, I'll try 1 cab (same gig last year, the 115 blew out the night before and it was the 1001RB-II, 210 EV cab and DI to the mains). While the head was at its settings I'd used with the EV speakers (210 + 115), this past gig I felt like I could finally hear/feel the bass next to the H&K 100w half stack I usually compete with.

Meanwhile, SW sent the casters advertised in the original copy, if not intended to be included with the used cab, just 'coz I asked. Ernie Ball casters that fit into my Fender keyboard amp didn't want to go into the GK cab :/ delivered casters were no problem :D
 
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#31
gpx1200 said:
guess ill have to concede to the bigger brains on this one, I was looking at it kind of backwards.
but I have been running setups like this for a long time with no sound ishue or driver failure so I guess blissful ignorance works for me to.
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Been there. Truth is I didn't even know it and it worked fine. But it wasn't correct. If I'd pushed it hard something would have blown. But I didn't.
 

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