Hi all, and sorry if think that you have heard this one before...
I have two Ampeg cabs, an SVT 210AV and a PF-115HE.
They are both 8 ohm, so if I chain the two the resulting impedance will be 4 ohm.
I'm planning to use these cabs with an Ampeg PF-500, which at 4 ohm is rated 500 watt.
Now the question.
Since the power ratings of the cabs are 200 watt and 450 watt respectively, how will they "manage" the 500 watt provided by the head?
Since they have the same impedance, will they share equally the 500 watts?
If so, pushing the head at full volume will blow the 210AV?
Thanks,
Andrea
I have two Ampeg cabs, an SVT 210AV and a PF-115HE.
They are both 8 ohm, so if I chain the two the resulting impedance will be 4 ohm.
I'm planning to use these cabs with an Ampeg PF-500, which at 4 ohm is rated 500 watt.
Now the question.
Since the power ratings of the cabs are 200 watt and 450 watt respectively, how will they "manage" the 500 watt provided by the head?
Since they have the same impedance, will they share equally the 500 watts?
If so, pushing the head at full volume will blow the 210AV?
Thanks,
Andrea