Anyway,,I understand that cabinets can be of of different ohms.. so do amp heads have ohms ratings as well..do you need to match the head to the cabinet with the same amount of ohms?
If the amp has a solid state output section, you need to know the minimum load it is rated for. As has been said, 2 ohms and 4 ohms minimum is common. Check the amp's specs.
If the amp has a tube output section, show the amp the expected load. Some tube amps expect one specific impedance. If the amp has a 4 ohm output, then hook up one 4 ohm cab or two 8 ohm cabs in parallel.
Other tube amps have two or possibly three options. For example some tube bass amps have 2, 4, and 8 ohm outputs.
The way the jacks are labeled can sometimes be misleading/confusing. Make sure you understand the correct way to hook up cabs, and ask an expert if you get confused.
Here's an example (Orange AD200B MkIII:
The labelling is a bit confusing as it appears there are two 4 ohm outputs and one 8 ohm output. The amp actually has a 4 ohm output and an 8 ohm output. However the 4 ohm output has two jacks in parallel. The load should be 4 ohms total for both of these jack.
- Run one 4 ohm cab on either 4 ohm jack.
- Run two 8 ohm cabs, one speaker connected to each 4 ohm jack.
- Combined load of two 8 ohm cabs in parallel is 4 ohms.
- Daisy chain two 8 ohm cabs to one of the 4 ohm jacks.
- Combined load of two 8 ohm cabs in parallel is 4 ohms.
- Run one 8 ohm cab on the 8 ohm jack.
- Do not run two 4 ohm cabs as the total load would be 2 ohms.
And what happens if you run two cabinets,,? And what happens if you run two different ohm ratings? Confused about this stuff
It depend on if the connection is series or parallel. In most instances the connection will be parallel.
If the connection is series, simply add the impedance of each cab. 8 + 8 = 16 ohms. 8 + 4 = 12 ohms, 4 + 4 = 8 ohms, etc.
If the connection is parallel and both cabs are the same impedance, simply divide the impedance of one cab by the number of cabs. For example if you have a pair of 8 ohms the impedance is 8/4 = 2 ohms.
If you connect two cabs with different impedance in parallel, use this formula where Z is impedance:
For example if you have an 8 ohm cabinet and a 4 ohm cabinet:
When you use multiple cabs you also need to consider how power is shared.
If both cabs are the same impedance then they share the power equally.
It's preferred to use matching cabs. Adding a matching cab in parallel gives the following results:
1. Combined Impedance = 1/2
2. Combined Power Handling = 2X
3. Combined Sensitivity = +3dB
If the impedance is not the same, the way the share power depends on if the connection is series or parallel.
If you have 8 ohm and 4 ohm cabs in parallel, the 4 ohm cab gets 2/3 of available power and the 8 ohm cab gets 1/3. Make sure to consider how much power is available and the power rating of each cab.
For example if the amp can make 600W and the 8 ohm cab is rated 400W and the 4 ohm cab is rated 200W you can't use all of the available power. At full power the 8 ohm cab will get 200W, which is safe. However the 4 ohm cab will get 400W, which double it's power rating. In this example, you can only use 300W. 200W goes to the 4 ohm cab and 100W goes to the 8 ohm cab.
It's generally not a good idea to use dissimilar cabs in series. The math says the 8 ohm cab will draw 2/3 of the power and the 4 ohm cab will get 1/3. But series connections can produce confounding results because the actual impedance at a given frequency varies by speaker design.