So here's the problem, i've got an 800 watt 4 ohm amp that has 2 outputs. I have 3 speaker cabinets that i'd like to use with this head. A 4x10 400 watts, a 2x10 200 watts, and a 1x15 thats also 200 watts. All 3 are 8 ohms.
Looking at the wiring the 10" speakers are wired parallel, and are 8 ohms. The cabs only have one input. If i were to add a second 1/4" plug to the 2x10, thats parallel to the original input, could i have a cable connecting those two and have the total be 400 watts at 8 ohms? I'm fairly experienced with wiring and electronics. And i know that plugging two of my cabs in it makes the head run at 4 ohms, 8+8=4. But would the 3rd cabs impedance factor in if i do this? Or still come out to 8+8=4?
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Looking at the wiring the 10" speakers are wired parallel, and are 8 ohms. The cabs only have one input. If i were to add a second 1/4" plug to the 2x10, thats parallel to the original input, could i have a cable connecting those two and have the total be 400 watts at 8 ohms? I'm fairly experienced with wiring and electronics. And i know that plugging two of my cabs in it makes the head run at 4 ohms, 8+8=4. But would the 3rd cabs impedance factor in if i do this? Or still come out to 8+8=4?
l
