• TalkBass has been independent since 1998. Add your voice.
    Create a free account to reply to discussions, view embedded media, and browse with fewer display ads.
    Join freeLog in
    Want zero display ads or expanded classifieds tools? Compare plans.

Volume pot value for Stellartone

Well it cares. Try to put a 25K pot there ;)

But probably not in the case where you replace a 500K by a 1Meg

A 25k pot would simply decrease the output impedance to the point that you would sound like crap. That's more of an issue with resistive loading against the pickup coils than the functionality of the tone control.

To my knowledge, the Tonestyler is simply a network of different RC filters. The behavior of each filter is certainly going to change as you alter the signal impedance, but you will just have slightly different effects from each position. The exact behavior of each filter is going to change with different pickups, and combinations of pickups in the signal path, anyways. It's quite difficult to pin down the exact frequency cutoffs, given the frequency-dependent nature of a complex impedance, and the fact that the impedance also changes with control settings.

1M Ohms is a rather uncommon pot value in basses, for two reasons. First off, the majority of players find some amount of resistive loading against the pickup coils to be desirable. (Though a lot of people prefer minimal resistive loading for a brighter tone.) Second, in some cases, the taper of the control comes into question with a very high value pot, since a series resistance is added between the pickup and output, that increases very quickly as you start to roll the volume down.
 
A 25k pot would simply decrease the output impedance to the point that you would sound like crap. That's more of an issue with resistive loading against the pickup coils than the functionality of the tone control.

To my knowledge, the Tonestyler is simply a network of different RC filters. The behavior of each filter is certainly going to change as you alter the signal impedance, but you will just have slightly different effects from each position. The exact behavior of each filter is going to change with different pickups, and combinations of pickups in the signal path, anyways. It's quite difficult to pin down the exact frequency cutoffs, given the frequency-dependent nature of a complex impedance, and the fact that the impedance also changes with control settings.

1M Ohms is a rather uncommon pot value in basses, for two reasons. First off, the majority of players find some amount of resistive loading against the pickup coils to be desirable. (Though a lot of people prefer minimal resistive loading for a brighter tone.) Second, in some cases, the taper of the control comes into question with a very high value pot, since a series resistance is added between the pickup and output, that increases very quickly as you start to roll the volume down.

Not trying to be too picky, but:
You're forgetting the pickup is an inductance, they form not an RC but RLC network together with stellartone's capacitors, producing different resonant frequency peaks. Loading the RLC with additional resistive load will reduce the Q of the network (flatten the peak), there could be audible difference depending on how much load you introduce...
 
Not trying to be too picky, but:
You're forgetting the pickup is an inductance, they form not an RC but RLC network together with stellartone's capacitors, producing different resonant frequency peaks. Loading the RLC with additional resistive load will reduce the Q of the network (flatten the peak), there could be audible difference depending on how much load you introduce...

I was talking about the Stellartone, itself, which is an RC filter network. (Or so I've heard. Could just be capacitors, so I don't want to make assumptions when I'm not yet certain.) The pickups are indeed an LCR resonant circuit with an inductive impedance.
 
I was talking about the Stellartone, itself, which is an RC filter network. (Or so I've heard. Could just be capacitors, so I don't want to make assumptions when I'm not yet certain.) The pickups are indeed an LCR resonant circuit with an inductive impedance.

Sure, that's why I was telling in my last post that we're talking the same matters. Reading carefully helps understand we're not disagreeing at all ;)