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I like this idea. Is there a way to simulate an HPF like Broughton's in Logic before dropping $100 on one?You could use a HPF in your signal chain to improve definition![]()
The string may be fatter but it still rests on the same pointsThe diameter is thicker though so even if it vibrates less off the center it still takes more space between string and fret. My experience is action goes up a bit or there’s fret buzz. Once you file the nut slots and get intonation right in first frets .
I retract my statement. My experience with a short scale 5 was going to a higher gauge B was a lot more clank and fret noise. Must have been due to something else being off.The string may be fatter but it still rests on the same points
No, you are right, a thicker gauge strings will have more travel when it vibrates, therefore needing more clearance space between the strings and the frets, and therefore potentially clankier compared to a thinner gauge string with the same setup.I retract my statement. My experience with a short scale 5 was going to a higher gauge B was a lot more clank and fret noise. Must have been due to something else being off.
I'm using an ancient version of Garageband only, Logic should have a lot more options, see below.I like this idea. Is there a way to simulate an HPF like Broughton's in Logic before dropping $100 on one?
I had a HPF control on my Bergantino HP Forté, but I never really played with it and have since sold it.
This is my bass with the specs, though I'm pretty sure the neck is maple and not ash.
Given two strings of different mass (say, a 120 and a 145 from the same product line) but same vibrating length, tension and plucking force applied, I would indeed expect the more massive one to have more momentum and excursion at midpoint. Please note that equal tension and length but different mass necessarily entails a different pitch.I thought a lighter string needed more room to vibrate, whereas a thicker string under more tension is by definition, tighter and requires less space to vibrate?The problem with larger gauges is they need more room to vibrate
That’s my understanding, too. I remember playing a P with some seriously big flats on it - they felt like they didn’t move at all! Mind you I was playing 40-95 rounds at the time.Given two strings of different mass (say, a 120 and a 145 from the same product line) but same vibrating length, tension and plucking force applied, I would indeed expect the more massive one to have more momentum and excursion at midpoint. Please note that equal tension and length but different mass necessarily entails a different pitch.
However, having the same two strings at the same length but also tuned to the same pitch, I would expect the lower tension of the less massive one - compounded with a higher flexibility - to decidedly trump the higher acceleration of the other, with a resulting wider excursion, and a need for more fretboard clearance, from the former.
[Of course, real-world conditions are more complicated than that: for example, the plucking hand of the player will tend to automatically adjust to the lower tension and wider movement of the less massive string (again, pitch and length being equal), and exert a lighter, not equal, force to it.]
Wait a minute. That's the bass you play and you want to buy a Mustang? I love Mustangs. But dude. Seriously. There's no way you're gonna be happy with a Mustang coming from that.
As for your original questions, I have a LaBella RX .130 on my Mustang. Whenever I change the strings, I have a DR set with a .125 B ready and waiting. I'm still very much in the experimentation phase.
Theoretically if the gauge is doubled at same pitch, scale, brand,type, the amplitude is halved and conversely, given the same parameters, if the gauge is halved the amplitude is doubled. From that you can discern that if you went from a 100 E for example to a 110 E, you can do the equation (.100/.110=.909) multiplied by A (where A is the action set for the smaller gauge in this case). Say the action is bog standard 2.4mm, than .909x2.4mm = 2.18mm for the lower amplitude 110. If going down a gauge from 110 to 100 it would be .110/.100 = 1.1 multiplied by the action for the larger gauge 2.18x1.1 = 2.40mm etc etcGiven two strings of different mass (say, a 120 and a 145 from the same product line) but same vibrating length, tension and plucking force applied, I would indeed expect the more massive one to have more momentum and excursion at midpoint. Please note that equal tension and length but different mass necessarily entails a different pitch.
However, having the same two strings at the same length but also tuned to the same pitch, I would expect the lower tension of the less massive one - compounded with a higher flexibility - to decidedly trump the higher acceleration of the other, with a resulting wider excursion, and a need for more fretboard clearance, from the former.
[Of course, real-world conditions are more complicated than that: for example, the plucking hand of the player will tend to automatically adjust to the lower tension and wider movement of the less massive string (again, pitch and length being equal), and exert a lighter, not equal, force to it.]