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That would put twice as much power in the 2x10 as the 4x10.
True, but 'that's the way we've always done it' is hardly a compelling reason to do so. The combination of a 2x10 and 4x10 is a good one, but only if the impedances are properly matched so that each ten receives the same power input.
How would you do that Bill? a 4Ω 410 and an 8Ω 210? which would be 3.something overall Ω's
That's why I mentioned the 16 ohm 2x10/8 ohm 4x10 option, for a total 5.3 ohm load that most amps would be comfortable with. 16 ohm 2x10s are rare, but it's just a 4 ohm 2x10 with the drivers wired series instead of parallel.How would you do that Bill? a 4Ω 410 and an 8Ω 210? which would be 3.something overall Ω's
It would be an overall impedance of 2.67 ohms, and yes - with that arrangement each speaker would be receiving the equal power.
Now explain what happens when an amp that will only go down to 4ohms (as "most" do) is given a 2.67 ohm load.
This is where the uninformed get into trouble and was my original point about worrying about getting the exact amount of watts to each speaker without careful regard for what your amp can handle.
so, why is using an 8 ohm 210 and an 8 ohm 410 together such a big deal?
So what if the 210 gets more power. The 410 has twice the speaker surface area than the 210.
Wouldn't that make them sound more even in terms of volume?
And what about guitarist who use a 412+212 setup, or a 212 or 112 combo with a 412 extension cab?
No. The way to think of this is if all six drivers were in the same box, as a 6x10. For them all to have the same output they would have to be wired in exactly the same way as they would to arrive at the 2:1 impedance ratio of 2x10 to 4x10. You would not wire a 6x10 so that half the power was going to two of the drivers with the other half split amongst the remaining four.The 410 has twice the speaker surface area than the 210. Wouldn't that make them sound more even in terms of volume? ?