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That's what I thought (I forget the proper engineering term for this differential in distribution), so imagine my surprise when I see that SWR and others appear to recommend this mismatching practice in their documentation.IvanMike said:"if you hook up a 4 ohm cabinet and an 8 ohm cabinet to an amp that can power a 2 ohm load, the 4 ohm cabinet will get twice the wattage as the 8 ohm one. "
Jeb said:Would "daisy chaining" two parellel wired 8 ohm cabs to one amp output, and ditto to the second amp output (So 4 cabs, 2 daisy chained per output) result in a 2 ohm load?
I'm talking about running 4 8 ohm monitors in a 2 daisy chain configuration through a single power amp rated at 4 ohms with 2 outputs (if that makes sense - I'm not sure that I'm clearly wording it but...).
Does that make sense? Would the above configuration result in a 2 or 4 ohm load?
Jeb said:Thanks. Lets say you have a 4 ohm cab and in that cab are 4 10" speakers. How are they wired? Series? What is the impedence of each speaker?

lol - you are absolved my childtommytoughnuts said:i am eternely in your debt ivanmike you are my new god![]()
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Surgeon said:If anyone is willing to entertain another question.
Bridging--I just read Joris' fine FAQ and finally have an idea what this means, but still have a few questions. If I buy an amp with two channels--and bridge it to my cab it gets the power from both channels right? But, the minimum ohm load of the amp doubles--is this correct? So an amp with 2ohm minimum, if bridged would now have a 4 ohm minimum?
How does one accomplish the bridging--is it a control on the amp, a special connector?![]()
Sorry, but I'm doing my homework before buying a new amp and keep coming across things that I don't fully understand.
Thanks in advance.
Surgeon said:Bridging--I just read Joris' fine FAQ and finally have an idea what this means, but still have a few questions. If I buy an amp with two channels--and bridge it to my cab it gets the power from both channels right? But, the minimum ohm load of the amp doubles--is this correct? So an amp with 2ohm minimum, if bridged would now have a 4 ohm minimum?
How does one accomplish the bridging--is it a control on the amp, a special connector?![]()