- Feb 12, 2006
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- Disclosures
- Development Engineer-Mesa Boogie, Development Engineer-Genzler (pedals), Product Support-Genz Benz
I don’t think you are understanding how this works.But the actual power source is one or more batteries, which are at 12VDC, so the power calculation needs to be done for that voltage. The line voltage used by the amplification is secondary and will only be applicable if the inverter is able to supply 120VAC under load.
If a bass amp is rated to draw 3 amps at 1/8 power (fairly large amp), the sizing for battery life is based on this long term average by multiplying the current by the line voltage giving 360 watts, then multiplying by the inverter efficiency of say 80% or 420 watts.
Now you look at the battery capacity. Multiply the AH by the voltage and you get watt-hours. Say your battery is 12V and 100 AH, that would be 1200 Watt-hours but a standard lead acid car battery has discharge limits of about 50% which gives you 600 watt-hours of capacity.
Now, divide the capacity by the load and you end up with the hours of run time, or in this case 600WH/420W or about an hour and a half.
For inverter SIZING, it must be capable of supporting the dynamic load which includes the short term peak currents. A good rule of thumb for class D bass amps is roughly 50% of the audio power, converted back to AC line current. So if the amp was rated at 800 watts into the load being driven, that would be 400 watts, which is the minimum the inverter would need to be rated for independent of the battery side of things.