The problem is that 18s are slower than 10s. Its because of the size and weight of the cone - that's simple physics. A sports car and a pickup truck can have the same engine - which one goes faster? The one with the smallest moving mass.
It is simple physics, especially when all the factors are included...
The motor is stronger in a driver with a heavier moving mass, otherwise the damping becomes unworkable.
The strength of the motor to moving mass ratio determine the maximum slew rate of the diaphragm, at lower frequencies the required slew rate is lower, at higher powers the slew rate becomes greater.
In HF drivers, even with very low moving mass, the accelerations are much greater due to the higher frequency, thus the slew rate requirements are higher. This is why you see such high motor strengths in HF drivers... not because of the moving mass but because of the accelerations involved. The relationships are below:
P = W / T
P = F x V
P = M x A x V
What I think you are trying to say is that at some point, as the frequency increases, there is no longer the system bandwidth, or available slew rate to accurately reproduce the signal. There is also group delay, or propagation delay (depending on your perspective), but this is not the same thing as being slower. Every mechanical system has this variable.
If the driver was in fact slower, the frequency would fall as the signal was reproduced, which of course can not occur.