Ampeg Isovent - Jack Plate Circuit Board.

[Redbrangus]

Nope, the incandescent varies in voltage with temperature.
Well known
Semiconductors also don't follow the ohms law rules - for different reasons

But I think I might be beginning to understand what you've been trying to say to me...that an incandescent lamp isn't truly an 'ohmic device', because the transfer function deviates so significantly from what is generally considered to be a resistor. Yes? Sorry to be so dim. So to speak.

 

[agedhorse]

Actually, an incandescent lamp varies in resistance with temperature, which causes the voltage/current change. But at any point in time, the ratio of resistance to voltage conforms to Ohm's law. Just because a circuit doesn't exhibit a linear transfer function doesn't mean it doesn't conform to the laws of physics.

Correct, and to describe this at all points in time requires non-linear math, it becomes a calculus problem very quickly. This is why it's often solved quickly and easily though less accurately) via a graphical method.

 

[DJ Bebop]

With all due respect, I am going to take the Jack Plate and Schematic Diagram to a friend, and while I am at work doing my job, have him ReWire the Jack Plate minus the Crossover Circuit Board, and see what this does.

What you all have said is the Crossover is NOT part of the equation, when the 210s and 215s are connected to the Crossover Board, but at least this way we can fully Exclude the Crossover Circuit Board.

 

[lokikallas]

If the 15s, out side of the cabinet, with the 210s disengaged, still resonates, then the 15s are the “problem”. The jack plate circuit board is not the same thing as a crossover. The crossover is just a single component on the circuit board. If you disengage the tweeter you bypass the crossover.

 

[DJ Bebop]

If the 15s, out side of the cabinet, with the 210s disengaged, still resonates, then the 15s are the “problem”. The jack plate circuit board is not the same thing as a crossover. The crossover is just a single component on the circuit board. If you disengage the tweeter you bypass the crossover.

We don't know if he disengaged the 10s. I asked that back aways. Waiting for a response. But you are right about the crossover. As that has been expressed by many here so far. Also waiting for a response on that as well.

 

[40Hz]

I've always thought his steadfast resistance to AC was rooted, at least in part, in the fact that he just plain didn't understand it.

You’re in good company. George Westinghouse himself always said Edison never really understood AC.

 

[40Hz]

We don't know if he disengaged the 10s. I asked that back aways. Waiting for a response. But you are right about the crossover. As that has been expressed by many here so far. Also waiting for a response on that as well.

I suspect there might have been some psychological as well as technical issues raised by a few of his responses.

 

[Jeff Scott]

You’re in good company. George Westinghouse himself always said Edison never really understood AC.

 

[DJ Bebop]

View attachment 3677607

The cats!

 

[seamonkey]

But I think I might be beginning to understand what you've been trying to say to me...that an incandescent lamp isn't truly an 'ohmic device', because the transfer function deviates so significantly from what is generally considered to be a resistor. Yes? Sorry to be so dim. So to speak.

Yes! that's all. It's not Ohmic that's how it's used to protect tweeters.

 

[crazyBassClown]

Yes! that's all. It's not Ohmic that's how it's used to protect tweeters.

Well, technically a resistor isn't either then, because if you heat a resistor up to the temperatures a light bulb filament reaches it's resistance will also increase in a similar fashion. To achieve this you would at the minimum have to place it in a vacuum as well though or it will burn up long before you reach these temps.
Invalid Link Removed

 

[Redbrangus]

Resistors, like most electronic components, have an specified operating range over which they do maintain their 'ohmic' qualities.

 

[agedhorse]

Every component has variations from purely linear operation. Fortunately most are close enough to linear to be able to avoid the more complex math.

Just because a resistance element varies with temperature doesn't mean that it doesn't behave according to Ohm's law at each point along the temperature curve. That's exactly why integral calculus and differential equations are used to describe the behavior with respect to ohm's law.

 

[BassmanPaul]

That's exactly why integral calculus and differential equations.

Hey I remember them!! I got 99% in math! LOL

 

[agedhorse]

Hey I remember them!! I got 99% in math! LOL

I'm jealous

 

[BassmanPaul]

I'm jealous

Unfortunately that was pre stroke.

I’m thick as a brick nowadays!

 

[DJ Bebop]

Every component has variations from purely linear operation. Fortunately most are close enough to linear to be able to avoid the more complex math.

Just because a resistance element varies with temperature doesn't mean that it doesn't behave according to Ohm's law at each point along the temperature curve. That's exactly why integral calculus and differential equations are used to describe the behavior with respect to ohm's law.

This is all well and good but, it's not answering my crossover question. Why the f'n F BOMB!

What do you see on this crossover that's causing THE F BOMB!

 

[Wasnex]

I'm jealous

So am I. I kept flunking & having to repeat my higher math classes, so eventually I declared a music major.

 

[farace]

Hey I remember them!! I got 99% in math! LOL

I think I got a 96% in honors calculus my freshman year in college. Unfortunately that was 1978, and I can't remember a single bit of it. I believe there is another law that states that what you remember from college is inversely proportional to how much of your student loan is paid off.

 

[thetragichero]

did somebody say olmec?