Take your A string and downtune it to match your E string. Now you have two E strings: a fat one and a skinny one. Play them and you'll find that the fat one is brighter.
Not my experience - I've done that; the E is duller.
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Take your A string and downtune it to match your E string. Now you have two E strings: a fat one and a skinny one. Play them and you'll find that the fat one is brighter.
Nope, the fatter strings were plucked harder to get the same amplitude.
I'd say plucking with comparable mechanical amplitudes, not striking it beyond reasonable limits.There's the rub - you're hearing a technique difference; striking a string vs plucking it.
I don't think so!
I don't think so!
A fatter string requires more tension in order to make it's higher mass resonate at a given frequency. More mass and tension require more energy for the same amplitude. Apart from the fundamental tone, harmonics appear along the string. The more energy, the more harmonics. As those harmonics are multiples of the fundamental frequency, the result will be a richer tone, not a fatter tone.
As the proof of the pudding is in the eating, I analysed the waveforms produced by both, thin and fat strings. It can be clearly seen that the percentage of harmonics versus the fundamental frequency depends on string gauge. In other words: Thinner strings produce more boom.
In the graph tone, gauge and tension are listed.
View attachment 3251726
Maybe the fat one sounds brighter because you reduced the tension on the skinny one.Take your A string and downtune it to match your E string. Now you have two E strings: a fat one and a skinny one. Play them and you'll find that the fat one is brighter.
That's exactly the point.Maybe the fat one sounds brighter because you reduced the tension on the skinny one.
the tension is building.... TOWARDS A CRITICAL MASS!!So the fat one is brighter because of greater mass or greater tension?
