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It is a relief to see this debate finally settled.
Now all the expensive cable companies will go out of business because noone is going to buy their cables nor their hype.
that slow-moving electrons create distortion as they haphazardly carry the signal along a wire, that cables store and release energy as signals propagate along them
Common mode noise rejection occurs in a balanced configuration where you have complementary signals on the two internal conductors.
It's not the complementary signals that give you CMR in a balanced connection but equal impedances to ground.
OK, but accepting that as a given (which I don't, really, but for the sake of argument...), how does that contribute to better noise rejection?
engedi1
Good article but the trouble is if people don't want to believe it they won't!
It's not the complementary signals themselves but the way they are treated on the receiving end. The noise picked up by the two lines tends to be the same, and the signals from the two lines are mixed in reverse polarity (what some call "out of phase"), so that the noise cancels. The matched impedance to ground is so that the induced noise on the two lines is of the same magnitude - also important for canceling.It's not the complementary signals that give you CMR in a balanced connection but equal impedances to ground.

Say, while I've got you EE's on the line, let me ask some advice about using transformers to change the z in and z out of my test rig. If I used a 1:15 step-up at the output of my audio converter, making the 50 ohm z out appear to be 11.25K; and if I used a 2:1 step-down at the input, making the 1M z in appear to be 250K; and connected the cables under test from one xfo to the other; would that be a reasonable way of making the cables perform as though they were connected from an instrument with 11K z out to an amp with 250K z in?
It's not the complementary signals themselves but the way they are treated on the receiving end. The noise picked up by the two lines tends to be the same, and the signals from the two lines are mixed in reverse polarity (what some call "out of phase"), so that the noise cancels. The matched impedance to ground is so that the induced noise on the two lines is of the same magnitude - also important for canceling.
Simulating a 250k load (from 1M) can be easily achieved by a adding resistor in parallel with the input of your measuring device so the combined value is 250k. (R=330k approx). Putting a resistor in series with the output of your audio converter is similarly going to alter the impedance presented to the cable.
Far be it from me to say how you should conduct your tests but I would be inclined to do them at several values of source impedance, say 50 ohms which is close-ish to an active with volume at max**. 11k for passive at max and would also cover an active backed off, and a higher figure to represent a backed off volume of a passive say 100k.
Oh believe me, I know this all too well.You have to remember that you could come under very close scrutiny and much criticism, especially if you find that there are minimal differences between cables. (Some people claim they can hear a bat f@rt at 300 yards.)
You might be just simplifying it a bit (and I'm not sure I'll be making it LESS confusing) but the way I understand balanced connections, it seems you left out a few key parts.
First, the "complementary signals" have to be treated on both ends, not just the receiving end. Balanced connections take a signal, split it in two, reverse the phase on one line, send those two lines (+ground) through the cable, and then reverse one line's phase again on the other side before mixing the two lines to recreate the signal. So the polarity actually gets reversed twice. Mixing a signal with it's direct inverse (out of phase) cancels it out. If you just mixed the two signals without "re-flipping" the phase, you'd end up with nothing BUT the noise.
Signal "a" becomes A and -A on the cable. Noise comes in giving you A+N and -A+N. Then on the other end you flip it back, so -A+N becomes A-N. This converts the reversed line back to the original signal, AND reverses the phase of the noise on that line, so now you're mixing (A+N) and (A-N) getting A+A. N and -N cancel each other out.
So part of the magic in combating noise over a balanced connection is this signal split-flip-flip-mix process, which requires balancing circuitry on both ends, which is in the connected gear, NOT in the cable. An extra wire doesn't help this happen unless you're connecting a balanced output to a balanced input.
There may be other side-effects (which may or may not be beneficial) from using extra wires, twisted pairs, etc. in a normal non-balanced connection (like good ol' 1/4" instrument cables), but AFAIK the impact on noise is nowhere near that of a balanced connection.
Anyhow, hope this makes sense....